What is the length of line CB in the provided diagram?
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Understand the Problem
The question seems to involve a geometric problem based on the provided sketch of a rectangle (CODB) with a diagonal line intersecting at point C which forms angle of 54 degrees at point C. We need to figure out what the question is, it's likely asking for the length of some line.
Answer
$CE \approx 2.89$ m
Answer for screen readers
$CE \approx 2.89$ m
Steps to Solve
- Identify the unknown length
We need to find the length of the line extending from point $C$ at a $54^\circ$ angle to the side $OD$. Let's label the point where the line intersects $OD$ as $E$. Thus, we need to find the length of $CE$.
- Analyze the geometry of the problem
We can see that we have a rectangle $CODB$. We know that $CD = 24m$ and $CO = 1.7m$. We also have an angle of $54^\circ$ at point $C$. We can use the tangent function to relate the sides of the right triangle $\triangle COE$.
- Calculate the length of $OE$
Let $OE = x$. We have $\angle E CO = 54^\circ$. So, $\tan(54^\circ) = \frac{OE}{CO} = \frac{x}{1.7}$ $x = 1.7 \times \tan(54^\circ)$.
- Find $\tan(54^\circ)$
$\tan(54^\circ) \approx 1.376$
- Calculate $OE$
$OE = 1.7 \times 1.376 \approx 2.3392$
- Calculate $DE$
Since $OD = CD = 24m$, then $DE = OD - OE = 24 - 2.3392 = 21.6608$.
- Calculate $CE$ We can use the Pythagorean theorem to find the length of $CE$. In $\triangle COE$: $CE^2 = CO^2 + OE^2$ $CE^2 = 1.7^2 + 2.3392^2$ $CE^2 = 2.89 + 5.4718$ $CE^2 = 8.3618$ $CE = \sqrt{8.3618} \approx 2.89m $
$CE \approx 2.89$ m
More Information
The length of line $CE$ has been approximated to two decimal places.
Tips
- Forgetting to use the correct trigonometric function (tangent in this case).
- Incorrectly applying the Pythagorean theorem.
- Rounding errors during intermediate calculations.
- Confusing adjacent and opposite sides in the trigonometric ratios.
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