What does the following C code do? #include <stdio.h> #include <conio.h> #include <math.h> main() { int i; for (i=0; i<=30; i+=2) { printf ("%d\n",i); } printf ("\nHasta pronto");... What does the following C code do? #include <stdio.h> #include <conio.h> #include <math.h> main() { int i; for (i=0; i<=30; i+=2) { printf ("%d\n",i); } printf ("\nHasta pronto"); }
Understand the Problem
The question is asking to analyze the provided C code, which includes printing even numbers from 0 to 30 along with a final message. The high-level approach will involve explaining how the code functions, including the loop structure and output format.
Answer
Prints even numbers from 0 to 30 and 'Hasta pronto'.
The C code prints all even numbers from 0 to 30, each on a new line, and then prints 'Hasta pronto'.
Answer for screen readers
The C code prints all even numbers from 0 to 30, each on a new line, and then prints 'Hasta pronto'.
More Information
This code uses a for loop to iterate through even numbers and includes a farewell message in Spanish, which means 'See you soon'.
Tips
A common mistake might be using the wrong increment value or comparison operator, resulting in incorrect loop execution.
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