# What are the factors of 128?

#### Understand the Problem

The question is asking for the factors of the number 128. To solve it, we will find all the whole numbers that divide 128 without leaving a remainder.

1, 2, 4, 8, 16, 32, 64, 128

The factors of 128 are: 1, 2, 4, 8, 16, 32, 64, and 128.

#### Steps to Solve

1. Identify the definition of factors Factors are the integers that can divide a number without leaving a remainder. Therefore, we need to find all the whole numbers that evenly divide 128.

2. Start dividing from 1 to 128 Begin testing each whole number starting from 1. We will divide 128 by each number and check if the result is a whole number.

3. List the factors Continue this process until reaching 128. If the division results in a whole number, add that number to the list of factors.

For instance, checking:

• ( 128 \div 1 = 128 ) (Factor)
• ( 128 \div 2 = 64 ) (Factor)
• ( 128 \div 4 = 32 ) (Factor)
• ( 128 \div 8 = 16 ) (Factor)
• ( 128 \div 16 = 8 ) (Factor)
• ( 128 \div 32 = 4 ) (Factor)
• ( 128 \div 64 = 2 ) (Factor)
• ( 128 \div 128 = 1 ) (Factor)
1. Complete the list of factors At the end of this process, we will have found all the factors of 128.

The factors of 128 are: 1, 2, 4, 8, 16, 32, 64, and 128.

128 is a composite number, meaning it has factors other than 1 and itself. It is also a power of 2, specifically $2^7$. This is why its factors are all powers of 2.

#### Tips

• Forgetting to test all numbers up to 128.
• Misidentifying the factors by skipping some or not dividing properly.
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