Two small charged spheres, each with a charge of -10 μC, are 10 cm apart. Calculate the force between them.
Understand the Problem
The question is asking to calculate the force between two charged spheres when they are 10 cm apart. It involves applying Coulomb's law to find the force, given the magnitudes of the charges and the distance between them.
Answer
The force between the spheres is $F = 8.99 \, N$.
Answer for screen readers
The force between the charged spheres is $F = 8.99 , N$.
Steps to Solve
- Identify Known Values
We know the following:
- Charge of sphere 1: $q_1 = -10 , \mu C = -10 \times 10^{-6} , C$
- Charge of sphere 2: $q_2 = -10 , \mu C = -10 \times 10^{-6} , C$
- Distance between the spheres: $r = 10 , cm = 0.1 , m$
- Use Coulomb's Law
Coulomb's law states that the force ( F ) between two point charges is given by the formula:
$$ F = k \cdot \frac{|q_1 \cdot q_2|}{r^2} $$
where ( k ) is Coulomb's constant, approximately ( 8.99 \times 10^9 , N \cdot m^2/C^2 ).
- Substitute Values into the Formula
Now substitute the known values into the formula:
$$ F = 8.99 \times 10^9 \cdot \frac{|-10 \times 10^{-6} \cdot -10 \times 10^{-6}|}{(0.1)^2} $$
- Calculate the Force
Simplify and calculate the above expression:
$$ F = 8.99 \times 10^9 \cdot \frac{(10 \times 10^{-6})^2}{0.01} $$
$$ F = 8.99 \times 10^9 \cdot \frac{100 \times 10^{-12}}{0.01} $$
$$ F = 8.99 \times 10^9 \cdot 10^{-9} $$
- Final Calculation
Now compute ( F ):
$$ F = 8.99 , N $$
The force between the charged spheres is $F = 8.99 , N$.
More Information
This force is repulsive because both charges are negative, which means they push away from each other.
Tips
- Confusing the signs of the charges: Remember that like charges repel and opposite charges attract.
- Not converting units correctly: Ensure all units are in the standard system (e.g., meters for distance, coulombs for charge).
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