The void ratio of an unconsolidated soil heap of volume 1000 m³ is 1.0. If the soil heap is consolidated to a volume of 800 m³, the corresponding void ratio is __________. (round o... The void ratio of an unconsolidated soil heap of volume 1000 m³ is 1.0. If the soil heap is consolidated to a volume of 800 m³, the corresponding void ratio is __________. (round off up to 2 decimals) Read more

Steps to Solve

1. Identify initial conditions The initial volume of the soil heap is given as ( V_1 = 1000 , \text{m}^3 ) and the initial void ratio as ( e_1 = 1.0 ).

2. Calculate the initial void volume To find the initial void volume ( V_{v1} ), use the formula: [ V_{v1} = e_1 \times V_s ] Where ( V_s ) (the volume of solids) can be calculated as: [ V_s = \frac{V_1}{1 + e_1} = \frac{1000}{1 + 1} = 500 , \text{m}^3 ]

3. Find the initial void volume Now substituting to find ( V_{v1} ): [ V_{v1} = e_1 \times V_s = 1.0 \times 500 = 500 , \text{m}^3 ]

4. Calculate the final volume of the soil heap The final volume after consolidation is given as ( V_2 = 800 , \text{m}^3 ).

5. Determine final void volume To find the final void volume ( V_{v2} ): [ V_{v2} = V_{v1} - (V_1 - V_2) = 500 - (1000 - 800) = 500 - 200 = 300 , \text{m}^3 ]

6. Calculate the final void ratio The final void ratio ( e_2 ) can be calculated using: [ e_2 = \frac{V_{v2}}{V_s} = \frac{300}{500} = 0.6 ]