Solve the following MCQ: 1) The weight of a particle at the center of the Earth is: a) Infinite b) zero c) same as that at other places d) greater than at the poles. 2) Change in d... Solve the following MCQ: 1) The weight of a particle at the center of the Earth is: a) Infinite b) zero c) same as that at other places d) greater than at the poles. 2) Change in dimensions is known as: a) deformation b) formation c) contraction d) strain 3) S.I unit of stress is: a) N/m b) N/m² c) N²/m d) N/m³ 4) In case of coefficient of static friction (µs), kinetic friction (µk), and rolling friction (µr), which of the following relation is true: a) µs > µk > µr b) µs > µr > µk c) µr > µs > µk d) µr > µk > µs 5) If α, β and γ are coefficient of linear, area, length and volume expansion of a solid then: a) α:β:γ = 1:3:2 b) α:β:γ = 1:2:3 c) α:β:γ = 2:3:1 d) α:β:γ = 3:1:2
Understand the Problem
The question is asking to solve a multiple choice question (MCQ) related to physics concepts. The topics covered include gravitational force at the Earth's core, dimensional changes, the SI unit of stress, the relationship between coefficients of static, kinetic, and rolling friction, and the relationship between coefficients of linear, area, and volume expansion of a solid.
Answer
1) zero, 2) strain, 3) N/m², 4) µs > µk > µᵣ, 5) α:β:γ = 1:2:3
- b) zero
- d) strain
- b) N/m²
- a) µs > µk > µᵣ
- b) α:β:γ = 1:2:3
Answer for screen readers
- b) zero
- d) strain
- b) N/m²
- a) µs > µk > µᵣ
- b) α:β:γ = 1:2:3
More Information
- At the Earth's center, gravitational forces cancel out, resulting in zero weight.
- Strain is the change in dimension of a body which is subjected to some stress.
- The S.I. unit of stress is Newton per meter squared(N/m^2)
- Static friction is greater than kinetic friction, which is greater than rolling friction.
- The ratio of linear, area, and volume expansion is 1:2:3.
Tips
Make sure you understand the definitions and formulas related to each concept to avoid confusion.
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