In the following decomposition of 150.0 grams of potassium Chlorate, what volume of oxygen is made at STP? 2KClO3 (s) --> 2KCl (s) + 3O2 (g)
Understand the Problem
The question is asking to calculate the volume of oxygen produced at Standard Temperature and Pressure (STP) from the decomposition of 150.0 grams of potassium chlorate (KClO3). This requires using stoichiometry based on the balanced chemical equation provided: 2KClO3 (s) --> 2KCl (s) + 3O2 (g).
Answer
41.12 L of oxygen is produced at STP.
The volume of oxygen produced at STP is approximately 41.12 L
Answer for screen readers
The volume of oxygen produced at STP is approximately 41.12 L
More Information
STP, or Standard Temperature and Pressure, is defined as 0°C (273.15 K) and 1 atm of pressure. At STP, one mole of an ideal gas occupies a volume of 22.4 liters.
Tips
Make sure the chemical equation is balanced before performing stoichiometric calculations. Also, remember the molar mass of KClO3 is 122.55 g/mol.
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