If tan(A) = 1/2 and tan(B) = 1/3, find the value of tan(A + B).
Understand the Problem
The question requires us to find the value of (\tan(A + B)) given the values of (\tan(A)) and (\tan(B)). We can use the formula for the tangent of the sum of two angles:
[\tan(A + B) = \frac{\tan(A) + \tan(B)}{1 - \tan(A)\tan(B)}]
By substituting the given values into this formula, we can calculate the value of (\tan(A + B)).
Answer
$\frac{7}{4}$
Answer for screen readers
$\tan(A + B) = \frac{7}{4}$
Steps to Solve
- Write down the formula
The formula for the tangent of the sum of two angles is: $$\tan(A + B) = \frac{\tan(A) + \tan(B)}{1 - \tan(A)\tan(B)}$$
- Substitute the given values
We are given that $\tan(A) = \frac{2}{3}$ and $\tan(B) = \frac{1}{2}$. Substituting these values into the formula, we get:
$$\tan(A + B) = \frac{\frac{2}{3} + \frac{1}{2}}{1 - \frac{2}{3} \cdot \frac{1}{2}}$$
- Simplify the numerator
To simplify the numerator, $\frac{2}{3} + \frac{1}{2}$, we find a common denominator, which is 6. So,
$$\frac{2}{3} + \frac{1}{2} = \frac{2 \cdot 2}{3 \cdot 2} + \frac{1 \cdot 3}{2 \cdot 3} = \frac{4}{6} + \frac{3}{6} = \frac{7}{6}$$
- Simplify the denominator
To simplify the denominator, $1 - \frac{2}{3} \cdot \frac{1}{2}$, we first multiply the fractions:
$$\frac{2}{3} \cdot \frac{1}{2} = \frac{2 \cdot 1}{3 \cdot 2} = \frac{2}{6} = \frac{1}{3}$$
Then, subtract this result from 1:
$$1 - \frac{1}{3} = \frac{3}{3} - \frac{1}{3} = \frac{2}{3}$$
- Divide the numerator by the denominator
Now we have:
$$\tan(A + B) = \frac{\frac{7}{6}}{\frac{2}{3}}$$
To divide fractions, we multiply by the reciprocal of the denominator:
$$\tan(A + B) = \frac{7}{6} \cdot \frac{3}{2} = \frac{7 \cdot 3}{6 \cdot 2} = \frac{21}{12}$$
- Simplify the fraction
Finally, we simplify the fraction $\frac{21}{12}$ by dividing both the numerator and the denominator by their greatest common divisor, which is 3:
$$\frac{21}{12} = \frac{21 \div 3}{12 \div 3} = \frac{7}{4}$$
$\tan(A + B) = \frac{7}{4}$
More Information
The tangent function is periodic with a period of $\pi$, meaning that $\tan(x) = \tan(x + n\pi)$ for any integer $n$.
Tips
A common mistake is to incorrectly apply the tangent addition formula or to make errors when simplifying fractions. Ensure you correctly substitute the values for $tan(A)$ and $tan(B)$ and carefully perform the arithmetic operations. Also, double-check your fraction simplifications.
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