Hydrogen atom abstraction from which position would yield the most stable free radical intermediate during the reaction of bromine with 2,2,3-trimethylpentane?
Understand the Problem
The question is asking which hydrogen atom abstraction position in 2,2,3-trimethylpentane would produce the most stable free radical when reacted with bromine. This involves understanding the stability of free radicals based on their structure.
Answer
B) C2
The final answer is B) C2.
Answer for screen readers
The final answer is B) C2.
More Information
Tertiary free radicals are generally more stable than secondary or primary ones due to the stabilization offered by additional alkyl groups.
Tips
Ensure to consider the degree of the carbon atom for radical stability, with tertiary being the most stable.
Sources
AI-generated content may contain errors. Please verify critical information
Thank you for voting!
