How many nucleons are in a nucleus of the isotope of silver represented by the nuclide notation 109 47 Ag?
Understand the Problem
The question is asking for the total number of nucleons in the specified isotope of silver, which can be determined by analyzing the given nuclide notation.
Answer
$109$
Answer for screen readers
The total number of nucleons in the nucleus of the isotope $^{109}_{47} \text{Ag}$ is $109$.
Steps to Solve
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Understanding Nuclide Notation In the nuclide notation $^{109}_{47} \text{Ag}$, the number on the top (109) represents the mass number (A), which is the total number of nucleons in the nucleus. This includes both protons and neutrons.
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Identifying the Mass Number The mass number for this isotope of silver is 109. Therefore, we can directly conclude how many nucleons are present in the nucleus.
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Count the Nucleons Since the mass number ($A$) is equal to the total number of nucleons, we have: $$ \text{Number of Nucleons} = 109 $$
The total number of nucleons in the nucleus of the isotope $^{109}_{47} \text{Ag}$ is $109$.
More Information
The mass number of an isotope indicates the total number of protons and neutrons it contains. In this case, silver has a mass number of 109, meaning it has a total of 109 nucleons in its nucleus.
Tips
- A common mistake is confusing the atomic number (the number of protons) with the mass number. The mass number indicates the total nucleon count, while the atomic number tells you the number of protons only.
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