Given two decimal numbers A = 78 and B = 29, find A - B and B - A using the following methods: a) Signed 2's complement format using 8 bits. b) 9's complement format.

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Understand the Problem

The question is asking to find A-B and B-A given A=78 and B=29 using two different methods: signed 2's complement format using 8 bits, and 9's complement format.

Answer

a) 2's complement: $A-B = 49$, $B-A = -49$ b) 9's complement: $A-B = 49$, $B-A = 50$
Answer for screen readers

a) Using signed 2's complement (8 bits): $A - B = 49$ $B - A = -49$

b) Using 9's complement: $A - B = 49$ $B - A = 50$

Steps to Solve

  1. Convert A and B to binary (8 bits)

$A = 78_{10} = 01001110_2$ and $B = 29_{10} = 00011101_2$

  1. Calculate A - B using 2's complement To calculate $A - B$, we can calculate $A + (-B)$, where $-B$ is the 2's complement of $B$. First, find the 1's complement of B by inverting all bits: $1's\ complement\ of\ B = 11100010_2$ Then, add 1 to find 2's complement: $2's\ complement\ of\ B = 11100010_2 + 1_2 = 11100011_2$ Now, add A and the 2's complement of B: $A + (-B) = 01001110_2 + 11100011_2 = 00110001_2$ (ignoring the carry-out) $00110001_2 = 49_{10}$, so $A - B = 49$

  2. Calculate B - A using 2's complement To calculate $B - A$, we can calculate $B + (-A)$, where $-A$ is the 2's complement of $A$. First, find the 1's complement of A by inverting all bits: $1's\ complement\ of\ A = 10110001_2$ Then, add 1 to find 2's complement: $2's\ complement\ of\ A = 10110001_2 + 1_2 = 10110010_2$ Now, add B and the 2's complement of A: $B + (-A) = 00011101_2 + 10110010_2 = 11001111_2$ Since the result is negative (the leftmost bit is 1), we take the 2's complement of the result to find its magnitude: $1's\ complement\ of\ 11001111_2 = 00110000_2$ $2's\ complement\ of\ 11001111_2 = 00110000_2 + 1_2 = 00110001_2 = 49_{10}$ Since the sign bit was 1, $B - A = -49$

  3. Calculate A - B using 9's complement $A - B = 78 - 29$. Since both numbers are positive, we don't need to find their 9's complement. We can directly subtract them: Since we are using 9's complement, we need consider how 9's complement works with negative numbers. However, since $A > B$, we can perform direct subtraction: $78 - 29 = 49$

  4. Calculate B - A using 9's complement $B - A = 29 - 78$. Since $B < A$, we will get a negative result. Subtract A from B: $29 - 78 = -49$ To represent -49 in 9's complement, first find the 9's complement representation of 49. Since we're not given the number of digits to use for the 9's complement, we are assuming the numbers are padded to the same length when calculating the 9's complement. In this case both numbers have two digits, so there's no need to pad. 9's complement of $49 = (9-4)(9-9) = 50$ Therefore, $B - A = -49$ is represented as $50$ in 9's complement.

a) Using signed 2's complement (8 bits): $A - B = 49$ $B - A = -49$

b) Using 9's complement: $A - B = 49$ $B - A = 50$

More Information

In 2's complement, the most significant bit represents the sign of the number (0 for positive, 1 for negative). The range of numbers that can be represented with 8 bits in 2's complement is from -128 to 127. In 9's complement for a decimal number, each digit is subtracted from 9.

Tips

  • Forgetting to add 1 after taking the 1's complement to get the 2's complement.
  • Not taking the 2's complement of the negative result after addition to find the correct magnitude when using 2's complement.
  • Incorrectly calculating the 9's complement.
  • Incorrectly converting between decimal and binary numbers.
  • Not accounting for the sign when performing 2's complement.

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