Find whether or not the first polynomial is a factor of the second polynomial: (i) 3x + 2, 3x^4 + 5x^3 - x^2 + 13x + 10; (ii) x^2 + 1, x^4 - 3x^3 - 4x^2 + 3x + 2.

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Understand the Problem

The question is asking for the division of polynomials and requires the calculation of quotients and remainders. It also involves determining if one polynomial is a factor of another, which entails applying polynomial division principles.

Answer

The quotient is \( 2x + \frac{15}{2} \) and the remainder is \( 19 \).
Answer for screen readers

The quotient is ( 2x + \frac{15}{2} ) and the remainder is ( 19 ).

Steps to Solve

  1. Identify the Division Problem

We will divide the polynomial ( 4x^2 + 7x - 11 ) by ( 2x - 4 ).

  1. Set up Polynomial Long Division

Arrange the terms in decreasing order and set up the division:

$$ \begin{align*} & \quad 2x - 4 \quad , \big| \quad 4x^2 + 7x - 11 \end{align*} $$

  1. Perform the First Division Step

Divide the leading term of the dividend ( 4x^2 ) by the leading term of the divisor ( 2x ):

$$ \frac{4x^2}{2x} = 2x $$

Now multiply ( 2x ) by ( 2x - 4 ):

$$ 2x(2x - 4) = 4x^2 - 8x $$

Subtract this from the original polynomial:

$$ (4x^2 + 7x - 11) - (4x^2 - 8x) = 15x - 11 $$

  1. Repeat for the Next Term

Now divide the new leading term ( 15x ) by ( 2x ):

$$ \frac{15x}{2x} = \frac{15}{2} $$

Multiply ( \frac{15}{2} ) by the entire divisor:

$$ \frac{15}{2}(2x - 4) = 15x - 30 $$

Subtract this from the new dividend:

$$ (15x - 11) - (15x - 30) = 19 $$

  1. Summarize Results

The final quotient is:

$$ 2x + \frac{15}{2} $$

And the remainder is:

$$ 19 $$

The quotient is ( 2x + \frac{15}{2} ) and the remainder is ( 19 ).

More Information

When dividing polynomials, the process involves finding the quotient and remainder, similar to numerical long division. The divisor must not equal zero, and the result can provide insights into factorization.

Tips

  • Missing Terms: Ensure each step is written clearly; skip terms can lead to errors.
  • Incorrect Signs: Pay attention to positive and negative signs during subtraction.

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