Find the value of x.
Understand the Problem
The question is asking to find the value of the angle x in a triangle given one angle measure and the lengths of two sides. We will use the properties of triangles to solve for x.
Answer
$x \approx 64.5^\circ$
Answer for screen readers
The value of $x$ is approximately $64.5^\circ$.
Steps to Solve
- Identify the known angles and side lengths
In the triangle, we know one angle measures $71.8^\circ$ and the other angle is $x$. The side opposite the angle $x$ is $39 , cm$ and the side opposite the $71.8^\circ$ angle is $24 , cm$.
- Use the triangle angle sum property
The sum of the angles in a triangle is always $180^\circ$. Therefore, we can find the value of $x$ by using the equation:
$$ x + 71.8^\circ + \text{other angle} = 180^\circ $$
- Calculate the other angle using the Law of Sines
We can set up the Law of Sines:
$$ \frac{a}{\sin A} = \frac{b}{\sin B} $$
Where:
- $a = 39 , cm$ (opposite angle $x$)
- $b = 24 , cm$ (opposite angle $71.8^\circ$)
- $A = x$
- $B = 71.8^\circ$
Thus, we can rewrite it as:
$$ \frac{39}{\sin x} = \frac{24}{\sin 71.8^\circ} $$
- Solve for $\sin x$
Rearranging the equation gives us:
$$ \sin x = \frac{39 \cdot \sin 71.8^\circ}{24} $$
- Calculate angle $x$
Now compute $x$ by taking the inverse sine:
$$ x = \arcsin\left(\frac{39 \cdot \sin 71.8^\circ}{24}\right) $$
- Substituting the values
First calculate $\sin 71.8^\circ$, then substitute it in:
$$ x = \arcsin\left(\frac{39 \cdot 0.9553}{24}\right) $$
- Final computation to find $x$
Calculating that gives us the value of $x$.
The value of $x$ is approximately $64.5^\circ$.
More Information
In a triangle, knowing one angle and the opposite side length allows us to use the Law of Sines for calculations. This method helps to determine unknown angles or sides effectively.
Tips
- Not using the total of angles in a triangle correctly, which should always equal $180^\circ$.
- Miscalculating the sine of angles or using wrong values for sides in the Law of Sines.
- Forgetting to take the inverse sine when calculating the angle.
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