Find the solution of the system of equations: -7x + 4y = -32 and 9x - 2y = 38.

Question image

Understand the Problem

The question is asking us to find the solution to a system of two linear equations. The equations given are -7x + 4y = -32 and 9x - 2y = 38. To solve this, we typically look for values of x and y that satisfy both equations simultaneously.

Answer

The solution to the system of equations is \( (4, -1) \).
Answer for screen readers

The solution to the system of equations is ( (4, -1) ).

Steps to Solve

  1. Rewrite the equations for easier manipulation

The equations are: $$ -7x + 4y = -32 $$ $$ 9x - 2y = 38 $$

  1. Rearrange the first equation to isolate y

From the first equation, solve for ( y ): $$ 4y = 7x - 32 $$ $$ y = \frac{7x - 32}{4} $$

  1. Substitute y in the second equation

Substitute ( y ) into the second equation: $$ 9x - 2\left(\frac{7x - 32}{4}\right) = 38 $$

  1. Clear the fraction

Multiply every term by 4 to eliminate the fraction: $$ 4(9x) - 2(7x - 32) = 4(38) $$ This gives: $$ 36x - 14x + 64 = 152 $$

  1. Combine like terms

Combine the ( x ) terms and simplify: $$ 22x + 64 = 152 $$

  1. Isolate x

Subtract 64 from both sides: $$ 22x = 152 - 64 $$ $$ 22x = 88 $$

Now divide by 22: $$ x = \frac{88}{22} $$ $$ x = 4 $$

  1. Substitute x back to find y

Now substitute ( x = 4 ) back into the rearranged equation for ( y ): $$ y = \frac{7(4) - 32}{4} $$ $$ y = \frac{28 - 32}{4} $$ $$ y = \frac{-4}{4} $$ $$ y = -1 $$

  1. Final solution

Thus, the solution to the system of equations is: $$ (x, y) = (4, -1) $$

The solution to the system of equations is ( (4, -1) ).

More Information

This type of problem is a classic example of solving simultaneous linear equations, where both equations are true for the same ( (x, y) ) pair. It's often solved using substitution or elimination methods.

Tips

  • Forgetting to distribute correctly when clearing fractions.
  • Mistakenly combining constants and variables when simplifying.
  • Not checking the solution by substituting back into the original equations.

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