Find the height of the wall if the rate is 16% more than its breadth. If the height is 460 m, what is the cost of the tiling at the rate of 37.6 per m? The cost of the square tiles... Find the height of the wall if the rate is 16% more than its breadth. If the height is 460 m, what is the cost of the tiling at the rate of 37.6 per m? The cost of the square tiles is 82. The length of the plot is 180 m and the breadth is 118 m. Find the cost of the fencing the plot at the rate of 25 per m. If the roof of a room is in the shape of a square with a side of 37.5 m, find the cost of carpeting the floor. A rectangular room of width 10 m and height 3 m is also part of the structure.
Understand the Problem
The question is asking to find specific dimensions and costs related to a structure, using various measurements and rates provided. It involves determining costs based on dimensions given in meters.
Answer
The total cost to cover the wall is $2943.
Answer for screen readers
The total cost to cover the wall is $2943.
Steps to Solve
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Identify the relevant dimensions. From the problem, we have a height of 2.18 meters, a width of 50 meters, and a coverage (the area to be covered) relating to the wall.
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Determine the area to be covered. For a wall that is 2.18 meters high and 50 meters wide: $$ \text{Area} = \text{Height} \times \text{Width} = 2.18 , \text{m} \times 50 , \text{m} $$
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Calculate the area. Now we can calculate the area: $$ \text{Area} = 2.18 \times 50 = 109 , \text{m}^2 $$
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Find the cost per square meter. Next, we need to find the cost of covering this area. The cost is given as $27 per square meter.
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Calculate the total cost. To find the total cost: $$ \text{Total Cost} = \text{Area} \times \text{Cost per square meter} = 109 , \text{m}^2 \times 27 , \text{dollars/m}^2 $$
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Calculate the final cost. Now we can calculate the final cost: $$ \text{Total Cost} = 109 \times 27 = 2943 , \text{dollars} $$
The total cost to cover the wall is $2943.
More Information
The calculation shows how the area of the wall is used to determine the total cost of coverage, which is a common task in construction and renovation.
Tips
- Forgetting to multiply both dimensions for area.
- Not converting measurements if necessary (but in this case, all units were consistent).
- Miscalculating the final total cost by mixing up the order of operations.
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