En dos recipientes se tienen 20 L de gasolina y 700 ml de mercurio. Halla sus respectivas masas en kilogramos. Datos: dgasolina = 0,8 g/cm³; dmercurio = 13,6 g/cm³.

Steps to Solve

1. Convert liters to cubic centimeters for gasoline

We know that 1 L = 1000 cm³. Therefore, 20 L is equal to:

$20 \text{ L} \times \frac{1000 \text{ cm}^3}{1 \text{ L}} = 20000 \text{ cm}^3$

2. Calculate the mass of gasoline

Using the formula $M = V \times D$, where $V = 20000 \text{ cm}^3$ and $D = 0.8 \text{ g/cm}^3$:

$M = 20000 \text{ cm}^3 \times 0.8 \text{ g/cm}^3 = 16000 \text{ g}$

3. Convert grams to kilograms for gasoline

Since 1 kg = 1000 g, we have:

$16000 \text{ g} \times \frac{1 \text{ kg}}{1000 \text{ g}} = 16 \text{ kg}$

4. Convert milliliters to cubic centimeters for mercury

Since 1 ml = 1 cm³, 700 ml is equal to 700 cm³.

5. Calculate the mass of mercury

Using the formula $M = V \times D$, where $V = 700 \text{ cm}^3$ and $D = 13.6 \text{ g/cm}^3$:

$M = 700 \text{ cm}^3 \times 13.6 \text{ g/cm}^3 = 9520 \text{ g}$

6. Convert grams to kilograms for mercury

Since 1 kg = 1000 g, we have:

$9520 \text{ g} \times \frac{1 \text{ kg}}{1000 \text{ g}} = 9.52 \text{ kg}$