Consider a capacitor with a capacity of 5 µF connected to a 1.5 V battery. What is the charge deposited on each of the plates of the capacitor?
Understand the Problem
The question asks to calculate the charge deposited on the plates of a capacitor given its capacitance and the voltage of the battery connected to it. We can use the formula Q = CV to solve this problem, where:
- Q is the charge
- C is the capacitance
- V is the voltage.
Answer
A) $7.5 \times 10^{-6} C$
Answer for screen readers
A) $7.5 \times 10^{-6} C$
Steps to Solve
- Identify the given values
Capacitance $C = 5 \mu F = 5 \times 10^{-6} F$ Voltage $V = 1.5 V$
- Apply the formula $Q = CV$
Use the formula to calculate the charge $Q$:
$Q = CV = (5 \times 10^{-6} F) \times (1.5 V)$
- Calculate the charge $Q$
$Q = 7.5 \times 10^{-6} C$
A) $7.5 \times 10^{-6} C$
More Information
The charge stored in a capacitor is directly proportional to the capacitance and the voltage across it. The unit of charge is Coulombs (C).
Tips
A common mistake is forgetting to convert microfarads ($\mu F$) to farads (F) before performing the calculation. Another mistake can be not knowing the formula $Q=CV$
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