Consider 2 Kr samples at 293 K, each with N = 6 × 10^23 atoms, but one with V = 25 L and the other with V = 50 L. Based on Figure 1, how many times as great is λ for the 50 L sampl... Consider 2 Kr samples at 293 K, each with N = 6 × 10^23 atoms, but one with V = 25 L and the other with V = 50 L. Based on Figure 1, how many times as great is λ for the 50 L sample as λ for the 25 L sample?
Understand the Problem
The question asks about the relationship between the mean free path (λ) of Krypton (Kr) atoms in two samples with different volumes (25 L and 50 L) but the same number of atoms (N) and temperature (T). It refers to a 'Figure 1' which is not provided, implying it provides relevant information or a formula that can be used to understand this relationship. The question then asks how many times greater λ would be for the 50 L sample compared to the 25 L sample. This means we need to find a relationship between the mean free path and volume, while keeping the number of atoms and temperature constant.
Answer
C. 2
The final answer is C. 2
Answer for screen readers
The final answer is C. 2
More Information
Based on the provided context, λ (mean free path) is directly proportional to the volume (V) when the number of atoms (N) and temperature (T) are constant. Therefore, if the volume doubles from 25 L to 50 L, λ also doubles. Thus, λ for the 50 L sample is two times as great as λ for the 25 L sample.
Tips
Pay close attention to the relationships between variables presented in figures when answering questions.
Sources
- Question 37 Answer and Explanation _ACT June 2015 Form 73C ... - exam.actexam.net
- Solved Passage VI For gas atoms in a state of random motion - Chegg - chegg.com
- [PDF] о о - SCIENCE TEST - AWS - core-docs.s3.us-east-1.amazonaws.com
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