Calculate the molar mass for Mn2O3, an oxide of manganese.
Understand the Problem
The question is asking for the calculation of the molar mass of the compound Mn2O3, which is an oxide of manganese. To find the molar mass, we will sum the molar masses of the constituent elements (manganese and oxygen) in the given ratio as per the chemical formula.
Answer
The molar mass of Mn2O3 is \( 159.88 \, \text{g/mol} \).
Answer for screen readers
The molar mass of Mn2O3 is ( 159.88 , \text{g/mol} ).
Steps to Solve
- Identify the elements and their quantities
In the compound Mn2O3, we have 2 manganese (Mn) atoms and 3 oxygen (O) atoms.
- Find the molar mass of each element
The molar mass of manganese (Mn) is approximately 54.94 g/mol.
The molar mass of oxygen (O) is approximately 16.00 g/mol.
- Calculate the total mass from manganese
To calculate the total mass contributed by manganese, multiply the number of manganese atoms by its molar mass:
$$
\text{Total mass from Mn} = 2 \times 54.94 , \text{g/mol}
$$
- Calculate the total mass from oxygen
Similarly, calculate the total mass contributed by oxygen:
$$
\text{Total mass from O} = 3 \times 16.00 , \text{g/mol}
$$
- Sum the total masses to find the overall molar mass
Now, add the total masses from manganese and oxygen to find the molar mass of Mn2O3:
$$
\text{Molar mass of Mn}_2\text{O}_3 = (\text{Total mass from Mn}) + (\text{Total mass from O})
$$
The molar mass of Mn2O3 is ( 159.88 , \text{g/mol} ).
More Information
The molar mass calculated reflects the combined weight of the elements present in the compound. Understanding molar masses is crucial in chemistry, especially when dealing with stoichiometry in chemical reactions.
Tips
- Forgetting to multiply the molar mass by the number of atoms for each element can lead to inaccurate totals. Always ensure to account for the coefficients in the chemical formula.
- Not using the correct molar mass values for elements can result in incorrect calculations.
