Calculate the force required to give a body with a weight of 980 N an acceleration of 1 m/s².

Steps to Solve

1. Calculate the mass of the body

We know that weight $W = mg$, where $W$ is the weight, $m$ is the mass, and $g$ is the acceleration due to gravity.

We are given $W = 980 , \text{N}$ and we know that $g \approx 9.8 , \text{m/s}^2$. So, we can find the mass $m$ by rearranging the formula: $m = \frac{W}{g}$ $m = \frac{980 , \text{N}}{9.8 , \text{m/s}^2} = 100 , \text{kg}$

2. Calculate the force required

We use the formula $F = ma$, where $F$ is the force, $m$ is the mass, and $a$ is the acceleration We have $m = 100 , \text{kg}$ and $a = 1 , \text{m/s}^2$. So, $F = (100 , \text{kg}) \times (1 , \text{m/s}^2) = 100 , \text{N}$

3. Identify the correct answer choice We calculated the force to be 100 N. However, none of the options exactly match this answer and there are some OCR errors. Let's analyze the original options provided to pick the best fit: a. 9BD N looks like a misread of 980 N due to OCR, meaning the answer would be 980 N * 1. b. 980 N x 1 m/s² c. 980 N d. 9BD N/1 m/s

Since we want the result of multiplying the mass (derived from the weight) by the acceleration, option b, 980 N x 1 m/s² represents this operation. However, it's important to note that option b would give units that do not make sense, because Newtons already has $(\text{kg}*\text{m})/{\text{s}^2}$ units.