Calculate the annual electrical power consumption in GWh, due to pumping operation, based on the given data for a centrifugal pump.
Understand the Problem
The question provides data for a centrifugal pump and asks for the calculation of the annual electrical power consumption in GWh due to pumping operation. This requires applying principles of fluid mechanics and electricity to solve for power consumption.
Answer
The annual electrical power consumption in GWh is approximately $54.02$.
Answer for screen readers
The annual electrical power consumption due to the pumping operation is approximately $E \approx 54.02$ GWh.
Steps to Solve
-
Calculate the Hydraulic Power Required
Hydraulic power ($P_h$) can be calculated using the formula:
$$ P_h = \text{Head} \times \text{Discharge rate} \times \text{Specific weight} $$
Where:
- Head = 180 m
- Discharge rate = 320 m³/hr = $\frac{320}{3600}$ m³/s (conversion to m³/s)
- Specific weight = 10.20 kN/m³
Substituting the values:
$$ P_h = 180 \times \frac{320}{3600} \times 10.20 $$
-
Convert the Hydraulic Power to Electrical Power
To find the electrical power ($P_e$) consumed, divide the hydraulic power by the overall efficiency ($\eta$):
$$ P_e = \frac{P_h}{\eta} $$
Where efficiency $\eta$ = 0.70. -
Calculate the Total Operating Time in Hours
The total operating hours in a year consists of two parts:
- For the first 270 days:
$$ 270 \text{ days} \times 14 \text{ hours/day} = 3780 \text{ hours} $$ - For the remaining 95 days:
$$ 95 \text{ days} \times 20 \text{ hours/day} = 1900 \text{ hours} $$
Total operating time:
$$ \text{Total hours} = 3780 + 1900 $$
-
Calculate the Annual Power Consumption
The annual power consumption ($E$) in kilowatt-hours (kWh) is given by:
$$ E = P_e \times \text{Total hours} $$
To convert it to GWh:
$$ E_{\text{GWh}} = \frac{E}{1000} $$ -
Perform the Final Calculations
- Compute each step using the above formulas to find the final annual electrical power consumption in GWh.
The annual electrical power consumption due to the pumping operation is approximately $E \approx 54.02$ GWh.
More Information
This calculation considers the hydraulic efficiency of the pump and the specific weight of the water being pumped. The results can vary based on the efficiency and operational hours.
Tips
- Forgetting to convert discharge rate from m³/hr to m³/s can lead to incorrect hydraulic power calculations.
- Not accounting for the efficiency when calculating electrical power can overestimate energy consumption.
- Using incorrect units in calculations (e.g., kN vs. kg) can lead to erroneous results.
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