Calcular el Nivel de Exposición a Vibraciones (NEV) utilizando la información proporcionada en la imagen.

Understand the Problem
La imagen presenta el Nivel de Exposición a Vibraciones (NEV) para dos trabajadores. El objetivo es determinar el NEV total combinando los datos de exposición de ambos trabajadores, utilizando las fórmulas proporcionadas. Se dan los tiempos de exposición (t) y las aceleraciones (a) para cada trabajador.
Answer
$NEV \approx 3.3466 \text{ m/s}^2$
Answer for screen readers
$NEV \approx 3.3466 \text{ m/s}^2$
Steps to Solve
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Identify the formula The formula to calculate the combined Vibration Exposure Level (NEV) is: $$NEV = \sqrt{\frac{(t_1 \times a_1^2) + (t_2 \times a_2^2)}{t_1 + t_2}}$$
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Identify the values for each variable From the image, we have: $t_1 = 2 \text{ hrs}$ $a_1 = 2 \text{ m/s}^2$ $t_2 = 3 \text{ hrs}$ $a_2 = 4 \text{ m/s}^2$
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Substitute the values into the formula Substitute the values of $t_1$, $a_1$, $t_2$, and $a_2$ into the formula: $$NEV = \sqrt{\frac{(2 \times 2^2) + (3 \times 4^2)}{2 + 3}}$$
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Calculate the squares Calculate $2^2$ and $4^2$: $2^2 = 4$ $4^2 = 16$ $$NEV = \sqrt{\frac{(2 \times 4) + (3 \times 16)}{2 + 3}}$$
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Perform the multiplications Calculate $2 \times 4$ and $3 \times 16$: $2 \times 4 = 8$ $3 \times 16 = 48$ $$NEV = \sqrt{\frac{8 + 48}{2 + 3}}$$
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Perform the additions Calculate $8 + 48$ and $2 + 3$: $8 + 48 = 56$ $2 + 3 = 5$ $$NEV = \sqrt{\frac{56}{5}}$$
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Perform the division Calculate $\frac{56}{5}$: $\frac{56}{5} = 11.2$ $$NEV = \sqrt{11.2}$$
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Calculate the square root Calculate $\sqrt{11.2}$: $\sqrt{11.2} \approx 3.3466$ $$NEV \approx 3.3466$$
$NEV \approx 3.3466 \text{ m/s}^2$
More Information
The Vibration Exposure Level (NEV) is a measure of a worker's exposure to vibrations, taking into account both the magnitude of the acceleration and the duration of exposure. It is important for assessing and managing the risks associated with vibration exposure in the workplace.
Tips
A common mistake is not squaring the acceleration values ($a_1$ and $a_2$) before multiplying them by the exposure times ($t_1$ and $t_2$). Another mistake is to add the accelerations before squaring. Also, not including the units (m/s²) to the answer.
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