Assuming independent assortment, what proportion of the offspring from a dihybrid cross (GgYy x GgYy) will display the recessive phenotype for both traits?
Understand the Problem
The question asks about the proportion of offspring displaying recessive phenotypes for both traits in a dihybrid cross (GgYy x GgYy), assuming independent assortment. We need to understand Mendelian genetics and how allele combinations result in specific phenotypes. This is done through the multiplication rule.
Answer
1/16
Assuming independent assortment, the proportion of offspring displaying the recessive phenotype for both traits in a dihybrid cross (GgYy x GgYy) is 1/16.
Answer for screen readers
Assuming independent assortment, the proportion of offspring displaying the recessive phenotype for both traits in a dihybrid cross (GgYy x GgYy) is 1/16.
More Information
In a dihybrid cross where both parents are heterozygous for two traits (GgYy x GgYy), the expected phenotypic ratio in the offspring is 9:3:3:1. The '1' in this ratio represents the proportion of offspring that will display both recessive traits. This ratio assumes independent assortment, meaning that the alleles of different genes assort independently of one another during gamete formation.
Tips
A common mistake is to confuse the dihybrid cross ratio with the monohybrid cross ratio. The dihybrid cross deals with two genes and has a 9:3:3:1 ratio, whereas the monohybrid cross deals with only one gene and has a 3:1 ratio when both parents are heterozygous.
Sources
- Dihybrid Cross - The Biology Project - biology.arizona.edu
- 4.2.2: Dihybrid Crosses and Independent Assortment - bio.libretexts.org
- Dihybrid Cross Explained - YouTube - youtube.com
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