An explosive with a density of 1.2 g/cm³ has a heat of explosion equal to 900 cal/g. If the heat of explosion of ANFO with density of 0.8 g/cm³ is 950 cal/g, what is the bulk stren... An explosive with a density of 1.2 g/cm³ has a heat of explosion equal to 900 cal/g. If the heat of explosion of ANFO with density of 0.8 g/cm³ is 950 cal/g, what is the bulk strength of the explosive relative to ANFO (round off up to 2 decimals)? Read more

Steps to Solve

1. Identify the formula for bulk strength comparison

The formula to calculate the bulk strength of an explosive relative to ANFO is given by:

$$ \text{Bulk Strength} = \frac{D_2 \times H_2}{D_1 \times H_1} $$

Where (D_1) and (H_1) are the density and heat of explosion of ANFO, and (D_2) and (H_2) are the density and heat of explosion of the explosive in question.

2. Gather the required data

You need to have the following values:

• (D_1) (Density of ANFO)
• (H_1) (Heat of explosion of ANFO)
• (D_2) (Density of the explosive)
• (H_2) (Heat of explosion of the explosive)

Make sure these values are collected accurately for a correct computation.

3. Substitute the values into the formula

Replace the variables with the collected values in the formula. For example:

$$ \text{Bulk Strength} = \frac{D_2 \times H_2}{D_1 \times H_1} $$

If (D_1 = 0.8 , \text{g/cm}^3), (H_1 = 3.0 , \text{MJ/kg}), (D_2 = 1.2 , \text{g/cm}^3), and (H_2 = 6.0 , \text{MJ/kg}), substitute these values:

$$ \text{Bulk Strength} = \frac{1.2 \times 6.0}{0.8 \times 3.0} $$

4. Calculate the bulk strength

Perform the calculations step by step:

First calculate the numerator:

$$ 1.2 \times 6.0 = 7.2 $$

Next, calculate the denominator:

$$ 0.8 \times 3.0 = 2.4 $$

Finally, divide the numerator by the denominator:

$$ \text{Bulk Strength} = \frac{7.2}{2.4} $$

Which simplifies to:

$$ \text{Bulk Strength} = 3 $$