A man divides ₹16850 between his two sons in such a way that after 20 years both of his sons receive the same money. If the ages of the sons are 12 years and 16 years, and the rate... A man divides ₹16850 between his two sons in such a way that after 20 years both of his sons receive the same money. If the ages of the sons are 12 years and 16 years, and the rate of compound interest is 33 1/3%, find the share of each son.

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理解问题

This is a math question involving financial calculations. A person has divided 16850 Rs between his two sons in such a way that after 20 years, both sons receive the same amount of money. The two sons are currently 12 and 16 years old respectively. The rate of compound interest is 33 1/3 %. The goal is to find the share of each son.

回答

Elder son: 12800 Rs Younger son: 4050 Rs
屏幕阅读器的答案

Elder son's share = 12800 Rs Younger son's share = 4050 Rs

解决步骤

  1. Define variables

Let $x$ be the amount given to the elder son (16 years old) and $y$ be the amount given to the younger son (12 years old). The total amount is 16850 Rs, so we have: $$x + y = 16850$$

  1. Calculate the investment periods

The investment period for the elder son is $20 - 16 = 4$ years. The investment period for the younger son is $20 - 12 = 8$ years.

  1. Calculate the compound interest rate

The rate of compound interest is $33\frac{1}{3}% = \frac{100}{3}% = \frac{100}{3 \times 100} = \frac{1}{3}$.

  1. Set up the equation for equal returns

The amount each son receives after the investment period can be calculated using the compound interest formula: $Amount = Principal \times (1 + rate)^{time}$. Since both sons receive the same amount after their respective investment periods, we can set up the following equation:

$$x \left(1 + \frac{1}{3}\right)^4 = y \left(1 + \frac{1}{3}\right)^8$$ $$x \left(\frac{4}{3}\right)^4 = y \left(\frac{4}{3}\right)^8$$

  1. Simplify the equation Divide both sides by $\left(\frac{4}{3}\right)^4$: $$x = y \left(\frac{4}{3}\right)^4$$ $$x = y \left(\frac{256}{81}\right)$$

  2. Solve the system of equations

We have two equations: $$x + y = 16850$$ $$x = \frac{256}{81}y$$ Substitute the second equation into the first: $$\frac{256}{81}y + y = 16850$$ $$\frac{256y + 81y}{81} = 16850$$ $$\frac{337y}{81} = 16850$$ $$y = \frac{16850 \times 81}{337}$$ $$y = 50 \times 81 = 4050$$

  1. Calculate the value of x

Now substitute the value of $y$ back into the equation $x + y = 16850$: $$x = 16850 - y$$ $$x = 16850 - 4050$$ $$x = 12800$$

  1. Final Answer

The share of the elder son is 12800 Rs, and the share of the younger son is 4050 Rs.

Elder son's share = 12800 Rs Younger son's share = 4050 Rs

更多信息

This problem demonstrates how compound interest affects investments over different time periods. Even though the total investment is divided, the difference in investment duration ensures that both sons receive the same final amount.

提示

A common mistake is forgetting to account for the different investment periods of the two sons. Also, errors can arise in the simplification of compound interest equations.

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