A hiker shouts toward a vertical cliff and the echo is heard 4 s later. If the speed of the sound in air is 343 m/s, what is the distance between the hiker and the cliff?

Understand the Problem
The question requires you to calculate the distance between a hiker and a cliff, given the speed of sound and the time it takes for the echo to return. Note that the sound travels to the cliff and back, so the effective distance is twice the distance between the hiker and the cliff.
Answer
The distance between the hiker and the cliff is $686 \, \text{m}$.
Answer for screen readers
The distance between the hiker and the cliff is $686 , \text{m}$.
Steps to Solve
- Calculate the total distance traveled by the sound The sound travels from the hiker to the cliff and back, so we can use the formula $ distance = speed \times time $ to find the total distance the sound traveled. Given: Speed of sound, $v = 343 , \text{m/s}$ Total time for the echo to return, $t = 4 , \text{s}$
Using the formula: $ d = v \times t $ $ d = 343 , \text{m/s} \times 4 , \text{s} $ $ d = 1372 , \text{m} $
- Calculate the distance between the hiker and the cliff Since the sound travels to the cliff and back, the distance calculated in step 1 is twice the distance between the hiker and the cliff. To find the distance between the hiker and the cliff, we divide the total distance by 2. $ \text{Distance to cliff} = \frac{\text{Total distance}}{2} $ $ \text{Distance to cliff} = \frac{1372 , \text{m}}{2} $ $ \text{Distance to cliff} = 686 , \text{m} $
The distance between the hiker and the cliff is $686 , \text{m}$.
More Information
The echo phenomenon is used in various real-world applications like sonar to determine the depth of the sea or detect underwater objects. Also bats use echolocation to navigate.
Tips
A common mistake is to forget that the echo travels to the cliff and back. Therefore, the total distance the sound travels is twice the distance between the hiker and the cliff. Failing to divide the total distance by 2 will result in an incorrect answer.
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