A 6-pole lap-wound generator has 300 conductors. The induced emf per conductor is 5V. What is the generated voltage of the generator?
Understand the Problem
The question is asking to calculate the generated voltage of a 6-pole lap-wound generator with 300 conductors, where the induced emf per conductor is given as 5V. The solution involves using the formula for generated voltage in such generators.
Answer
The generated voltage of the generator is $150 \text{ V}$.
Answer for screen readers
The generated voltage of the generator is $150 \text{ V}$.
Steps to Solve
- Identify the formula for generated voltage To calculate the generated voltage ($V_g$) of a lap-wound generator, use the formula: $$ V_g = \frac{P \cdot E \cdot N}{60} $$ where:
- $P$ = number of poles
- $E$ = induced emf per conductor
- $N$ = number of conductors
- Insert the known values into the formula Given:
- $P = 6$ (number of poles)
- $E = 5 \text{ V}$ (induced emf per conductor)
- $N = 300$ (number of conductors)
Substituting these values in: $$ V_g = \frac{6 \cdot 5 \cdot 300}{60} $$
- Calculate the voltage Now perform the arithmetic operations: First calculate the numerator: $$ 6 \cdot 5 \cdot 300 = 9000 $$
Then divide by 60 to find the generated voltage: $$ V_g = \frac{9000}{60} = 150 \text{ V} $$
The generated voltage of the generator is $150 \text{ V}$.
More Information
In a lap-wound generator, the configuration allows for efficient generation of voltage. The number of poles and conductors directly influences the overall voltage, making the formulas used crucial for design and functionality.
Tips
- Neglecting the number of poles: Some might forget that the number of poles directly influences the total voltage output. It's essential to include it in calculations.
- Forgetting to divide by 60: Miscalculating the final step by not dividing by 60 based on the context of the formula can lead to incorrect results.
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