1. A sample of ethane $C_2C_6$ diffuses at a rate of $3.6 \times 10^{-6}$ mol/hr. An unknown gas under the same conditions diffuses at a rate of $1.3 \times 10^{-6}$ mol/hr. Calcul... 1. A sample of ethane $C_2C_6$ diffuses at a rate of $3.6 \times 10^{-6}$ mol/hr. An unknown gas under the same conditions diffuses at a rate of $1.3 \times 10^{-6}$ mol/hr. Calculate the molar mass of the unknown gas. 2. Which gas in each of the following pairs diffuses more rapidly and what are the relative rates of diffusion? a. Kr and $O_2$ b. $N_2$ and acetylene ($C_2H_2$)

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Understand the Problem

The image contains two chemistry questions related to diffusion. The first question asks to calculate the molar mass of an unknown gas given the diffusion rates of ethane and the unknown gas. The second question asks which gas in each of the provided pairs diffuses more rapidly and what are the relative rates of diffusion.

Answer

1. 281.3 g/mol 2. a. O2 (2.22) b. N2 (1.07)
  1. The molar mass of the unknown gas is 281.3 g/mol.
  2. a. O2 diffuses more rapidly. The relative rate of diffusion is 2.22. b. N2 diffuses more rapidly. The relative rate of diffusion is 1.07.
Answer for screen readers
  1. The molar mass of the unknown gas is 281.3 g/mol.
  2. a. O2 diffuses more rapidly. The relative rate of diffusion is 2.22. b. N2 diffuses more rapidly. The relative rate of diffusion is 1.07.

More Information

The rate of diffusion is inversely proportional to the square root of its molar mass. This relationship is Graham's Law.

Tips

Always remember to calculate the molar mass (in g/mol) correctly before using it in Graham's Law equation and the relative rate should be a number greater than 1.

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