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Questions and Answers

What is the empirical formula of copper oxide determined from the ratio of copper to oxygen?

  • Cu3O
  • Cu2O (correct)
  • CuO2
  • CuO

If a student burns 9 g of magnesium, what mass of magnesium oxide will be formed?

  • 12 g
  • 15 g (correct)
  • 18 g
  • 24 g

What volume of carbon dioxide is produced from burning 30 g of carbon in excess oxygen?

  • 24 L
  • 56 L (correct)
  • 30 L
  • 28 L

In the reaction between magnesium and oxygen, what is the total mass of magnesium oxide produced from 48 g of magnesium?

<p>80 g (B)</p> Signup and view all the answers

What is the ratio of moles of magnesium to moles of oxygen in the formation of magnesium oxide?

<p>2:1 (A)</p> Signup and view all the answers

What is the relative molecular mass of calcium oxide, CaO?

<p>56 (A)</p> Signup and view all the answers

What is the empirical formula of glucose?

<p>CH2O (D)</p> Signup and view all the answers

How do you find the molecular formula from the empirical formula?

<p>By multiplying the empirical formula by a whole number n. (B)</p> Signup and view all the answers

Given 5.4 g of copper oxide yields 4.8 g of copper, what is the mass of oxygen in copper oxide?

<p>0.6 g (C)</p> Signup and view all the answers

What percentage of calcium is present in calcium oxide, CaO?

<p>71.43% (A)</p> Signup and view all the answers

What is the percentage composition of oxygen in calcium oxide, CaO?

<p>28.57% (A)</p> Signup and view all the answers

What would the molecular formula of glucose be if it has a relative molecular mass of 180?

<p>C6H12O6 (A)</p> Signup and view all the answers

If n represents the number used to get the molecular formula from the empirical formula, what is true about the value of n?

<p>It is an integer greater than 0. (A)</p> Signup and view all the answers

Flashcards

Calculating mass of magnesium oxide from magnesium

To find the mass of magnesium oxide formed when a given mass of magnesium reacts, use the balanced chemical equation and molar ratios. The equation 2Mg + O2 → 2MgO indicates the stoichiometric relationship between magnesium and magnesium oxide.

Empirical formula of copper oxide

The simplest whole-number ratio of atoms in a compound. In the case of copper oxide, the ratio is 2:1 (Cu2O).

Calculating volume of CO2 from carbon

To determine the volume of carbon dioxide produced when a certain mass of carbon is burned, use the balanced chemical equation and molar volume (22.4 L/mol at STP).

Balanced chemical equation

A chemical equation that shows the same number of each type of atom on both sides of the equation.

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Stoichiometry

The calculation of reactants and products in chemical reactions using balanced equations.

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Percentage Composition

The percentage by mass of each element in a compound.

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Molecular Formula

Shows the actual number and type of atoms in a molecule.

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Empirical Formula

Shows the simplest whole-number ratio of atoms in a compound.

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Empirical Formula Calculation (Masses)

Calculating the empirical formula of a compound from the masses of elements.

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Relative molecular mass of CaO

The sum of the atomic masses of calcium and oxygen in CaO.

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Calculating percentage composition of CaO

Determines the percentage by mass of calcium and oxygen in calcium oxide.

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Molecular Formula Calculation

Finding the molecular formula from the empirical formula and relative molecular mass.

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Study Notes

Stoichiometry

  • Stoichiometry is the branch of chemistry that relates the amounts of reactants and products in a chemical reaction.
  • It is essential for determining the quantities of reactants needed to produce a specific amount of product.

Calculating Percentage Composition

  • To determine the percentage composition of an element in a compound:
    • Calculate the relative molecular mass of the compound.
    • Divide the atomic mass of the element by the relative molecular mass of the compound.
    • Multiply the result by 100 to get the percentage.

Example (CaO)

  • Relative molecular mass of CaO = 56
  • Percentage of Ca = (40/56) * 100 = 71.43%
  • Percentage of O = (16/56) * 100 = 28.57%

Empirical Formula Calculation

  • Molecular formula: Shows the number and types of atoms in a molecule.
  • Empirical formula: Shows the simplest whole number ratio of atoms in a compound.
  • Molecular formula = empirical formula * n (where 'n' is a whole number)

Example (Glucose)

  • Empirical formula of glucose = CH₂O
  • Relative molecular mass of glucose = 180
  • 180 = (12 + 2 + 16) * n
  • n = 6
  • Molecular formula of glucose = C₆H₁₂O₆

Calculating Empirical Formula from Masses

  • In an experiment involving a reaction between an oxide of copper and hydrogen, the mass of copper oxide can be used to determine the empirical formula.

Example (Copper Oxide):

  • If 5.4 g of copper oxide produces 4.8 g of copper, the mass of oxygen is 0.6 g.
  • Calculate the moles of each element (copper and oxygen).
  • Determine the ratio of copper to oxygen atoms to find the empirical formula (Cu₂O in this example).

Calculating Masses of Reactants/Products using Balanced Chemical Equation

  • Using balanced chemical equations(example Mg + O₂ → MgO).
  • To calculate the mass of magnesium oxide formed when 9 g of magnesium is burned in excess oxygen, use the molar ratio approach.
  • Example: Given the mass of a reactant, use stoichiometry to find the mass of the product.

Gas Volume Calculations

  • To determine the volume of CO₂ formed when 30 g of carbon are burned in excess oxygen, using the balanced chemical equation and molar volume information
  • Determine Moles of carbon
  • Calculate CO₂ volumes at standard temperature and pressure
  • Example: 30 g of carbon produced 56 L of CO₂.

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