Work, Power & Energy Quiz

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to Lesson

Podcast

Play an AI-generated podcast conversation about this lesson
Download our mobile app to listen on the go
Get App

Questions and Answers

What is the definition of work done by a force?

  • The product of energy and time
  • The product of mass and velocity
  • The total distance traveled by an object
  • The product of force and displacement in the direction of force (correct)

What is the unit of work?

  • Pascal
  • Watt
  • Joule (correct)
  • Newton

What is the work done when a force is acting perpendicular to the direction of displacement?

  • The work done is negative
  • The work done is maximum
  • The work done is zero (correct)
  • The work done is equal to the force itself

What is the work done by an external force of 50 N on a mass with displacement of 5 m when the angle between the force and displacement is 0°?

<p>250 J (D)</p> Signup and view all the answers

How is the work done by frictional force calculated when it acts opposite to displacement?

<p>By using the equation $W = -F.S$ (C)</p> Signup and view all the answers

Flashcards are hidden until you start studying

Study Notes

Work

  • Defined as the product of force and displacement in the direction of that force.
  • Work is classified as a scalar quantity, which means it has magnitude but no direction.
  • Mathematically represented by the equation:
    ( W = F \cdot S = |F| |S| \cos \theta )

Units and Dimensions of Work

  • The unit of work is Newton-meter (Nm) or Joule (J).
  • The dimensional formula for work is ( ML^2T^{-2} ).

Cases of Work

  • Force in the Direction of Displacement (θ = 0°):
    Work is maximized, calculated as:
    ( W = F \cdot S \cos 0° = F \cdot S )

  • Force Perpendicular to Displacement (θ = 90°):
    No work is done since the direction of force does not contribute to displacement:
    ( W = F \cdot S \cos 90° = 0 )

  • Force Opposite to Displacement (θ = 180°):
    Work is negative, indicating that the force opposes motion:
    ( W = F \cdot S \cos 180° = -F \cdot S )

Example Calculation of Work

  • Problem concerns a mass of 10 kg with a displacement of 5 m.

  • External Force: 50 N with an angle of 0° to the displacement.
    Work done by external force is calculated as:
    ( W_{ext} = 50 \times 5 \times 1 = 250 , J )

  • Frictional Force: 10 N with an angle of 180° to the displacement.
    Work done by frictional force is calculated as:
    ( W_{friction} = 10 \times 5 \times (-1) = -50 , J )

Studying That Suits You

Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

Quiz Team

More Like This

Work in Physics Quiz
5 questions
Physics Work and Force Concepts
5 questions

Physics Work and Force Concepts

OverjoyedMossAgate7323 avatar
OverjoyedMossAgate7323
Physics Work and Energy Concepts
5 questions

Physics Work and Energy Concepts

EntrancingPedalSteelGuitar7303 avatar
EntrancingPedalSteelGuitar7303
Use Quizgecko on...
Browser
Browser