Viral, Antiretroviral, Antimalaria, Chemo Medications

Filgrastim stimulates the immune system

May result in a high risk of birth defect, in which case multiple birth control methods may be required

Integrals of indefinite forms:

$\int(x^5 - x^{2/3} + 2x^{-1/2})dx = \frac{x^6}{6} - \frac{3x^{5/3}}{5} + 4x^{1/2} + C$

$\int(x^2 + 1)(x-2)dx = \int(x^3 - 2x^2 + x - 2)dx = \frac{x^4}{4} - \frac{2x^3}{3} + \frac{x^2}{2} - 2x + C$

$\int \frac{x^3 + 1}{x+1} dx = \int (x^2 - x + 1) dx = \frac{x^3}{3} - \frac{x^2}{2} + x + C$

$\int (\sqrt{x} + \frac{1}{\sqrt{x}})dx = \int (x^{1/2} + x^{-1/2})dx = \frac{2}{3}x^{3/2} + 2x^{1/2} + C$

$\int (2\cos x - 3\sin x)dx = 2\sin x + 3\cos x + C$

$\int (\sec^2 x + x)dx = \tan x + \frac{x^2}{2} + C$

$\int (x^2 + \sec x \tan x)dx = \frac{x^3}{3} + \sec x + C$

$\int (5e^x - \frac{3}{x})dx = 5e^x - 3\ln|x| + C$

$\int (2^x + 3^x)dx = \frac{2^x}{\ln 2} + \frac{3^x}{\ln 3} + C$

$\int \frac{1}{x^2 + 1} dx = \arctan x + C$

$\int \frac{1}{\sqrt{1 - x^2}} dx = \arcsin x + C$

Integrals of definite forms:

$\int_0^1 (x - 2x^3)dx = [\frac{x^2}{2} - \frac{x^4}{2}]_0^1 = \frac{1}{2} - \frac{1}{2} - (0 - 0) = 0$

$\int_{-1}^0 (x - 2x^3)dx = [\frac{x^2}{2} - \frac{x^4}{2}]_{-1}^0 = (0 - 0) - (\frac{1}{2} - \frac{1}{2}) = 0$

$\int_1^2 (\frac{1}{x^2} - \frac{1}{x^3})dx = [-\frac{1}{x} + \frac{1}{2x^2}]_1^2 = (-\frac{1}{2} + \frac{1}{8}) - (-1 + \frac{1}{2}) = -\frac{3}{8} - (-\frac{1}{2}) = \frac{1}{8}$

$\int_0^1 (x^e + e^x)dx = [\frac{x^{e+1}}{e+1} + e^x]_0^1 = (\frac{1}{e+1} + e) - (\frac{0}{e+1} + 1) = \frac{1}{e+1} + e - 1$

$\int_0^{\pi/2} (4\cos\theta - 3\sin\theta)d\theta = [4\sin\theta + 3\cos\theta]_0^{\pi/2} = (4\sin(\frac{\pi}{2}) + 3\cos(\frac{\pi}{2})) - (4\sin(0) + 3\cos(0)) = (4(1) + 3(0)) - (4(0) + 3(1)) = 4 - 3 = 1$

$\int_0^{\pi/3} (\sec x \tan x)dx = [\sec x]_0^{\pi/3} = \sec(\frac{\pi}{3}) - \sec(0) = 2 - 1 = 1$

$\int_1^2 \frac{(x^2 + 1)^2}{x^2}dx = \int_1^2 \frac{x^4 + 2x^2 + 1}{x^2}dx = \int_1^2 (x^2 + 2 + \frac{1}{x^2})dx = [\frac{x^3}{3} + 2x - \frac{1}{x}]_1^2 = (\frac{8}{3} + 4 - \frac{1}{2}) - (\frac{1}{3} + 2 - 1) = \frac{7}{3} + 2 - \frac{1}{2} = \frac{14 + 12 - 3}{6} = \frac{23}{6}$

$\int_0^1 (\sqrt{x^5} + \sqrt{x^4})dx = \int_0^1 (x^{5/4} + x^{4/5})dx = [\frac{4}{9}x^{9/4} + \frac{5}{9}x^{9/5}]_0^1 = (\frac{4}{9} + \frac{5}{9}) - (0 + 0) = \frac{9}{9} = 1$

$\int_1^e \frac{x^2 + x + 1}{x}dx = \int_1^e (x + 1 + \frac{1}{x})dx = [\frac{x^2}{2} + x + \ln|x|]_1^e = (\frac{e^2}{2} + e + \ln e) - (\frac{1}{2} + 1 + \ln 1) = \frac{e^2}{2} + e + 1 - \frac{1}{2} - 1 - 0 = \frac{e^2}{2} + e - \frac{1}{2}$

$\int_0^1 \frac{1}{x^2 + 1}dx = [\arctan x]_0^1 = \arctan 1 - \arctan 0 = \frac{\pi}{4} - 0 = \frac{\pi}{4}$

$\int_0^{1/2} \frac{1}{\sqrt{1 - x^2}}dx = [\arcsin x]_0^{1/2} = \arcsin(\frac{1}{2}) - \arcsin(0) = \frac{\pi}{6} - 0 = \frac{\pi}{6}$

$\int_4^9 \frac{2 + \sqrt{x}}{x}dx = \int_4^9 (\frac{2}{x} + \frac{\sqrt{x}}{x})dx = \int_4^9 (\frac{2}{x} + \frac{1}{\sqrt{x}})dx = [2\ln|x| + 2\sqrt{x}]_4^9 = (2\ln 9 + 2\sqrt{9}) - (2\ln 4 + 2\sqrt{4}) = 2\ln 9 + 6 - 2\ln 4 - 4 = 2\ln 9 - 2\ln 4 + 2 = 2\ln(\frac{9}{4}) + 2$

Antibiotics necessitate taking all the medication

Cilluns and cyclines lessen the effect of birth control, so different birth control methods should be taken.

Stop alcohol consumption while taking antibiotics

Azithromycin consumption should be on an empty stomach

Sulfa medication requires no sun exposure, with lots of water, and folic acid. Urine should be monitored for kidney efficiency.

Myacin is very toxic, nephron and ototoxic, and kidney toxic. Urine output needs to be monitored.