Vanishing and Exploding Gradient in Neural Networks
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Questions and Answers

What term is commonly used to refer to the problem of unstable gradients in neural networks?

  • Exploding gradient dilemma
  • Vanishing gradient problem (correct)
  • Unstable weight conundrum
  • Fluctuating loss issue

How is the gradient typically calculated in a neural network?

  • Manually by the network architect
  • Through forward propagation
  • Using convolutional layers
  • By applying backpropagation (correct)

What is the purpose of updating the weights in a neural network with the gradient?

  • To find the most optimal weights for minimizing total loss (correct)
  • To slow down the training process
  • To maximize the total loss
  • To introduce randomness in the model

Which concept is primarily affected by the vanishing gradient problem in neural networks?

<p>Weights of hidden layers (A)</p> Signup and view all the answers

What problem arises when multiplying terms greater than one in deep learning?

<p>Exploding gradient (C)</p> Signup and view all the answers

Where in the network does the exploding gradient problem predominantly occur?

<p>Early layers (D)</p> Signup and view all the answers

How does the vanishing gradient problem differ from the exploding gradient problem?

<p>Vanishing gradient decreases gradient size, exploding increases gradient size (B)</p> Signup and view all the answers

What effect does an exploding gradient have on weight updates during training?

<p>It greatly moves the weights (B)</p> Signup and view all the answers

Why does an exploding gradient lead to weights moving too far from their optimal values?

<p>Due to a large proportionate weight update (C)</p> Signup and view all the answers

In which case will increasing the number of large-valued terms being multiplied have a significant impact on the gradient size?

<p>When weights are large (C)</p> Signup and view all the answers

What is the main issue caused by the vanishing gradient problem?

<p>Weights in earlier layers of the network become stuck and do not update effectively. (D)</p> Signup and view all the answers

How does the vanishing gradient problem relate to weight updates?

<p>Small gradients lead to small weight updates that hinder network learning. (A)</p> Signup and view all the answers

Why do earlier weights in the network face the vanishing gradient problem more severely?

<p>Earlier weights require multiplying more small terms in the gradient calculation. (A)</p> Signup and view all the answers

What happens if the terms involved in calculating a weight's gradient are 'small'?

<p>The product of these terms becomes even smaller, affecting weight updates. (D)</p> Signup and view all the answers

How does a small gradient affect weight updating in a neural network?

<p>It leads to negligible weight changes that hinder overall learning. (B)</p> Signup and view all the answers

Why does updating a weight with a small value further exacerbate the vanishing gradient problem?

<p>Multiplying the small gradient by a small learning rate yields an even smaller update. (A)</p> Signup and view all the answers

Why is it important for weights in a neural network to update sufficiently?

<p>To help in minimizing the loss function effectively. (C)</p> Signup and view all the answers

How does a vanishing gradient impact the performance of a neural network?

<p>It hinders the ability of the network to learn effectively due to stuck weights. (C)</p> Signup and view all the answers

What consequence arises from weights being 'stuck' due to vanishing gradients?

<p>The weights fail to converge to optimal values, impairing network performance. (C)</p> Signup and view all the answers

How does updating a stuck weight with a very small value typically affect network learning?

<p>The weight remains stagnant, impeding learning progress throughout the network. (D)</p> Signup and view all the answers

Why do earlier weights have more difficulty overcoming vanishing gradients compared to later ones?

<p>The product of several small terms in earlier layers compounds, leading to smaller overall gradients. (B)</p> Signup and view all the answers
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