Understanding Enthalpy Change (∆H°)

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Questions and Answers

Under what specific conditions is enthalpy measured, and why are these conditions important?

Enthalpy is measured under standard conditions of 100 kPa pressure and a specified temperature, generally 298 K. These conditions are important for consistent and comparable measurements.

Explain how the overall energy change of a reaction is determined by the energy involved in bond breaking and bond formation.

The overall energy change is determined by the difference between the energy required to break bonds (endothermic, positive) and the energy released when bonds are formed (exothermic, negative).

How do energy level diagrams visually represent enthalpy changes, and what information can be inferred from them?

Energy level diagrams show the relative energy levels of reactants and products. They indicate whether a reaction is endothermic (reactants lower than products) or exothermic (reactants higher than products).

Explain why, in exothermic reactions, heat is considered 'given out,' and how this impacts the sign of the enthalpy change (H).

<p>In exothermic reactions, more energy is released in forming new bonds than is required to break existing ones, resulting in a net release of heat to the surroundings. This release of energy means the enthalpy change (H) is negative.</p> Signup and view all the answers

Define the enthalpy change of formation, and explain its significance in thermochemistry.

<p>The enthalpy change of formation is the enthalpy change when one mole of a substance is produced from its elements under standard conditions. It's significant because it provides a reference point for calculating other enthalpy changes.</p> Signup and view all the answers

Describe the key difference between the enthalpy change of formation and the enthalpy change of combustion. How does the central product differ in Hess's Law diagrams for each?

<p>The enthalpy change of formation refers to forming one mole of a substance from its elements, while the enthalpy change of combustion involves burning one mole of a substance completely in oxygen. In Hess's Law diagrams, formation diagrams have elements as the product, while combustion diagrams have $H_2O$ and $CO_2$ as the central product.</p> Signup and view all the answers

For Hess's Law diagrams, explain why the direction of the arrows is important and how it affects the calculation of enthalpy changes.

<p>The arrow direction indicates whether the reaction is going in the forward or reverse direction relative to the given enthalpy change. If a reaction goes against the arrow, the sign of its enthalpy change must be reversed in the calculation.</p> Signup and view all the answers

Explain the concept of Hess's Law and discuss why it's used to determine enthalpy changes for reactions that are not easily measured experimentally.

<p>Hess's Law states that the overall enthalpy change for a reaction is the same regardless of the route taken. It's used for reactions that are hard to measure directly because it allows calculating the enthalpy change using alternative, measurable reactions.</p> Signup and view all the answers

Describe the relationship between the measured temperature change in calorimetry and the energy change of a reaction. What does it mean for the temperature change ($\Delta T$) to be proportional to the energy change?

<p>In calorimetry, the measured temperature change (T) is directly proportional to the energy change of the reaction. This means that a larger temperature change indicates a greater amount of energy being either released or absorbed.</p> Signup and view all the answers

The equation (q = mc\Delta T) is fundamental to calorimetry. Explain each component of the formula.

<p>In the equation (q = mc\Delta T): `q` represents the energy change in Joules (J), `m` is the mass of the substance in grams (g), `c` stands for the specific heat capacity in J g C, and `T` is the temperature change in degrees Celsius (C).</p> Signup and view all the answers

Explain how extrapolating data in calorimetry helps to improve the accuracy of determining the temperature change at the beginning of a reaction.

<p>Extrapolating data in calorimetry helps account for heat loss or gain during the reaction. By extending the line of best fit back to the start of the reaction, a more accurate initial temperature change can be determined, minimizing errors from heat exchange with the surroundings.</p> Signup and view all the answers

Why are $\Delta H$ values obtained through calorimetry considered 'never completely accurate,' and what specific factors contribute to these inaccuracies?

<p>(\Delta H) values from calorimetry are 'never completely accurate' due to energy loss from the system. This can occur through conduction, convection, inaccuracies in measuring temperatures or because the specific heat capacity of the calorimeter is not accounted for.</p> Signup and view all the answers

How does insulating a calorimeter with a material like polystyrene help reduce heat loss, and why is using a lid also beneficial?

<p>Insulating a calorimeter with polystyrene reduces heat loss by minimizing conduction and convection to the surroundings. Using a lid helps to reduce heat loss by preventing convection and evaporation.</p> Signup and view all the answers

Define what is meant by 'specific heat capacity'.

<p>The specific heat capacity is defined as the energy required to raise the temperature of 1g of a substance by 1K without a change of state.</p> Signup and view all the answers

Define bond enthalpy and explain why it is described as an 'averaged' value.

<p>Bond enthalpy is the energy required to break one mole of a specific bond in the gaseous phase under standard conditions. It's an 'averaged' value because the energy to break a particular bond varies slightly depending on the specific molecule it's in.</p> Signup and view all the answers

Why do bond enthalpy values calculated experimentally often differ from those found in data books for the same bond?

<p>Experimental bond enthalpy values differ from data book values because the data book values are averaged over many compounds. The environment around the bond also affects its strength, so the bond enthalpy will change depending on the molecule.</p> Signup and view all the answers

Explain how bond enthalpy values can be used to predict the likelihood of a bond breaking first in a chemical reaction, and why this can be useful.

<p>Bonds with lower bond enthalpy values are more likely to break first in a chemical reaction because they require less energy to break. This information can be useful for understanding reaction mechanisms and predicting reaction pathways.</p> Signup and view all the answers

If a reaction requires breaking many strong bonds, or if it's endothermic overall, how might this affect the reaction rate at room temperature, and why?

<p>If a reaction requires breaking many strong bonds or is endothermic overall, it is likely to proceed slowly at room temperature because there may not be sufficient energy available to overcome the high energy barrier for bond breaking or the overall energy requirement of the reaction.</p> Signup and view all the answers

What does the (\Sigma) symbol mean in the context of bond enthalpy calculations?

<p>In bond enthalpy calculations, the capital sigma symbol, (\Sigma), denotes the &quot;sum of&quot;. It is used to indicate that you need to add up all the bond enthalpies for all the bonds broken and, separately, for all the bonds formed during the reaction.</p> Signup and view all the answers

Given the chemical equation $CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O$, outline how to calculate the enthalpy change for this reaction using bond enthalpies.

<ol> <li>Identify all bonds broken in the reactants ($CH_4$ and $O_2$) and all bonds formed in the products ($CO_2$ and $H_2O$). 2. Multiply each bond enthalpy by the number of times that bond appears in the equation. 3. Calculate the sum of the energy for all bonds broken and the sum of energy for all bonds formed. 4. Subtract the sum of the energies of bonds formed from the sum of the energies of bonds broken to find the enthalpy change.</li> </ol> Signup and view all the answers

Flashcards

Enthalpy Change (∆H°)

Heat energy change, represented by the symbol ∆H°, measured in standard conditions (100 kPa and usually 298 K).

Bond Breaking vs. Bond Forming

Breaking bonds requires energy input (endothermic), while forming bonds releases energy (exothermic).

Positive Enthalpy Change

When energy is taken in from the surroundings; ∆H is positive.

Calculating Overall Enthalpy Change

AH = energy to break bonds (positive) + energy to make bonds (negative).

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Endothermic Reactions

Reactions needing more energy to break bonds than make new ones. Overall ∆H is positive, heat is taken in.

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Exothermic Reactions

Reactions needing more energy to make new bonds than break existing ones, with heat being given out and AH is negative.

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Enthalpy Change of Reaction

Enthalpy change when quantities of substances in standard states react completely under standard conditions.

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Enthalpy Change of Formation

The enthalpy change when one mole of a substance is produced from its elements under standard conditions.

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Enthalpy Change of Combustion

The enthalpy change when one mole of a substance is burned completely in oxygen under standard conditions.

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Enthalpy Change of Neutralisation

Enthalpy change when solutions of acid and alkali react to produce one mole of water.

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Enthalpy Change of Atomisation

Enthalpy change when one mole of gaseous atoms is formed from an element in its standard state.

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Calorimetry

Experimental method for finding enthalpy change by measuring temperature change over time.

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Specific Heat Capacity

The specific capacity is the energy to raise 1g of a substance by 1K without a change of state.

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Sources of Error in Calorimetry

Related to heat loss, conduction, convection, or inaccuracies in measuring temperatures.

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Hess's Law

States that the overall enthalpy change for a reaction is the same, regardless of the route taken.

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Mean Bond Enthalpy

Break a particular bond, averaged out across compounds containing that bond.

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Bond Enthalpy Definition

The energy required to break one mole of the stated bond in a gaseous state, under standard conditions.

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Calculating Enthalpy Change Using Bond Enthalpies

Overall enthalpy change is equal to the sum of the bond enthalpies for the bonds broken minus the sum of the bond enthalpies for the bonds formed.

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Study Notes

Enthalpy Change (∆H°)

  • Enthalpy change represents the change in heat energy, symbolized as ∆H°.
  • Enthalpy is measured under standard conditions: 100 kPa pressure and a specified temperature, usually 298 K.
  • During a reaction, energy is absorbed to break bonds and released when bonds are formed. The overall energy change relies on the energy transfer in these processes.
  • An enthalpy change is positive when energy is absorbed from the surroundings.
  • An enthalpy change is negative when energy is released into the surroundings.
  • The overall enthalpy change (∆H) is calculated by adding the energy needed to break bonds (positive value) to the energy released when making bonds (negative value).
  • Energy level diagrams visually represent enthalpy changes in a reaction, indicating whether the reaction is endothermic or exothermic.
  • Endothermic reactions require more energy to break bonds than to form them, resulting in a positive overall ∆H and heat being absorbed from the surroundings.
  • Exothermic reactions release heat and have a negative ∆H, requiring more energy to form new bonds than break existing ones.

Measuring Enthalpy Change

  • The enthalpy change of reaction (∆rHo) refers to the enthalpy change when quantities of substances in standard states react completely under standard conditions.
  • The enthalpy change of formation (∆fHo) is the enthalpy change when one mole of a substance is produced from its elements under standard conditions.
  • The enthalpy change of combustion (∆cHo) refers to the enthalpy change when one mole of a substance is burned completely in oxygen under standard conditions.
  • The enthalpy change of neutralization (∆neutHo) is the enthalpy change when solutions of acid and alkali react together under standard conditions to produce one mole of water.
  • The enthalpy change of atomization (∆atHo) refers to the enthalpy change when one mole of gaseous atoms is formed from an element in its standard state.

Calorimetry

  • Calorimetry serves as an experimental method to determine enthalpy change by measuring temperature change over time.
  • Plotted data can be extrapolated to provide a precise temperature change value at the beginning of the reaction.
  • The measured change in temperature, ∆T, is proportional to the energy change, represented by the equation q = mc∆T, where q is energy change (J), m is mass (g), c is specific heat capacity (J g-1 °C-1), and ∆T is temperature change (°C).
  • The specific heat capacity refers to the energy required to raise 1g of a substance by 1K without changing its state.
  • Enthalpy change per mole (J mol-1) is calculated using the formula: ΔH = q / moles.
  • Calorimetry-derived ∆H values are never completely accurate because energy is easily lost from the system.
  • Heat loss can occur through conduction, convection, or temperature measurement inaccuracies.
  • Using a lid on the calorimeter and insulating it with a material like polystyrene helps minimize heat loss to the surroundings.
  • The specific heat capacity of the solution is taken to be 4.18 kJ mol-1, which is the value for water and not the actual solution.

Hess's Law

  • Energy in a reaction system is conserved, thus the overall enthalpy change for a reaction remains the same regardless of the pathway.
  • Hess's Law helps determine enthalpy changes for reactions not directly measurable experimentally, using a triangular cycle method with an intermediate product.
  • Hess’s Law uses a triangular cycle method where the direction of the arrows indicates whether the values should be added or taken away, being treated like vectors.
  • In triangular diagrams for enthalpies of formation, arrows point up from the central product (C) as both A and B are formed from the elements at C.
  • In triangular diagrams for enthalpies of combustion, arrows point towards the central product (always H2O and CO2) as both A and B burn to form products at C.

Bond Enthalpies

  • Bond enthalpy data is an averaged value representing the energy needed to break one mole of a bond in a gaseous state under standard conditions.
  • Different covalent bonds require different amounts of energy to break, values for which can be found experimentally using calorimetry methods.
  • Data book values are approximate averages, as bond enthalpy values calculated in this way will vary in each situation.
  • Mean bond enthalpy values indicate the energy needed to break a specific bond, averaged across compounds containing that bond.
  • Mean bond enthalpy values relate to bond strength and predict which bonds break first in a chemical reaction, with lower values indicating easier breakage.
  • Reactions requiring the breaking of many strong bonds or that are endothermic overall are likely to occur slowly at room temperature.
  • Mean bond enthalpy values calculate the overall enthalpy change for a reaction using the formula: ΔHreaction = ΣH(bonds broken) - ΣH(bonds formed).
  • The enthalpy change for a reaction equals the sum of the bond enthalpies for the bonds broken minus the sum of the bond enthalpies for the bonds formed.
  • Bond enthalpy values are often presented in tables to help identify bonds broken and formed when calculating overall enthalpy change.
  • For example, the enthalpy change for methane complete combustion in oxygen is calculated using given bond enthalpies, where bonds formed and broken are tallied up to find the net energy change.

Bond Enthalpy Example

  • Bond enthalpies in kJ mol-1: C-H is 413, O=O is 498, O-H is 464, and C=O is 799.
  • For methane combustion: CH4 + 2O2 → CO2 + 2H2O.
  • Total energy to form bonds: C=O x 2 = 1598 kJ/mol, H-O x 4 = 1856 kJ/mol.
  • Total energy to break bonds: C-H x 4 = 1652 kJ/mol, O=O x 2 = 996 kJ/mol.
  • Enthalpy change = (1652 + 996) - (1856 + 1598) = -806 kJ/mol.

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