Trigonometric Functions Values Quiz
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Questions and Answers

Tan(0°) = 0 - tan(30°) = √3/3 - tan(45°) = 1 - tan(60°) = √3 - tan(90°) = ______ - tan(120°) = -√3 - tan(135°) = -1 - tan(150°) = -√3/3 - tan(180°) = 0 - tan(210°) = √3/3 - tan(225°) = 1 - tan(240°) = √3 - tan(270°) = ______ - tan(300°) = -√3 - tan(315°) = -1 - tan(330°) = -√3 / 3 - tan(360°) = 0

none

Cos(0°) = 1 - cos(30°) = √3 / 2 - cos(45°) = √2 / 2 - cos(60°) = 1 / 2 - cos(90°) = ______ - cos(120°) = -1 / 2 - cos(135°) = -√2 / 2 - cos(150°) = -√3 / 2 - cos(180°) = -1 - cos(210°) = -√3 / 2 - cos(225°) = -√2 / 2 - cos(240°) = -1 / 2 - cos(270°) = ______ - cos(300°) = 1 / 2 - cos(315°) = √2 / 2 - cos(330°) = √3 / 2 - cos(360°) = 1

0

Sin(0°) = 0 - sin(30°) = 0.5 - sin(45°) = √2 / 2 - sin(60°) = √3 / 2 - sin(90°) = 1 - sin(120°) = √3 / 2 - sin(135°) = √2 / 2 - sin(150°) = 0.5 - sin(180°) = 0 - sin(210°) = -1 / 2 - sin(225°) = -√2 / 2 - sin(240°) = -√3 / 2 - sin(270°) = -1 - sin(300°) = -√3 / 2 - sin(315°) = -√2 / 2 - sin(330°) = -1 / 2 - sin(360°) = 0

none

Tan(0°) = 0 - tan(30°) = √3/3 - tan(45°) = 1 - tan(60°) = √3 - tan(90°) = ______ - tan(120°) = -√3 - tan(135°) = -1 - tan(150°) = -√3/3 - tan(180°) = 0 - tan(210°) = √3/3 - tan(225°) = 1 - tan(240°) = √3 - tan(270°) = ______ - tan(300°) = -√3 - tan(315°) = -1 - tan(330°) = -√3 / 3 - tan(360°) = 0

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Cos(0°) = 1 - cos(30°) = √3 / 2 - cos(45°) = √2 / 2 - cos(60°) = 1 / 2 - cos(90°) = ______ - cos(120°) = -1 / 2 - cos(135°) = -√2 / 2 - cos(150°) = -√3 / 2 - cos(180°) = -1 - cos(210°) = -√3 / 2 - cos(225°) = -√2 / 2 - cos(240°) = -1 / 2 - cos(270°) = ______ - cos(300°) = 1 / 2 - cos(315°) = √2 / 2 - cos(330°) = √3 / 2 - cos(360°) = 1

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Tan(0°) = 0 - tan(30°) = √3/3 - tan(45°) = 1 - tan(60°) = √3 - tan(90°) = ______ - tan(120°) = -√3 - tan(135°) = -1 - tan(150°) = -√3/3 - tan(180°) = 0 - tan(210°) = √3/3 - tan(225°) = 1 - tan(240°) = √3 - tan(270°) = ______ - tan(300°) = -√3 - tan(315°) = -1 - tan(330°) = -√3 / 3 - tan(360°) = 0

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Cos(0°) = 1 - cos(30°) = √3 / 2 - cos(45°) = √2 / 2 - cos(60°) = 1 / 2 - cos(90°) = ______ - cos(120°) = -1 / 2 - cos(135°) = -√2 / 2 - cos(150°) = -√3 / 2 - cos(180°) = -1 - cos(210°) = -√3 / 2 - cos(225°) = -√2 / 2 - cos(240°) = -1 / 2 - cos(270°) = ______ - cos(300°) = 1 / 2 - cos(315°) = √2 / 2 - cos(330°) = √3 / 2 - cos(360°) = 1

<p>0</p> Signup and view all the answers

Tan(180°) = 1

<p>False</p> Signup and view all the answers

Sin(90°) = 1

<p>True</p> Signup and view all the answers

Cos(270°) = -1

<p>False</p> Signup and view all the answers

Tan(360°) = 0

<p>True</p> Signup and view all the answers

Study Notes

Anglesen Sin, Cos, tan

  • Sin(0°) = 0, Sin(90°) = 1
  • Cos(0°) = 1, Cos(90°) = 0, Cos(180°) = -1, Cos(270°) = -1, Cos(360°) = 1
  • Tan(0°) = 0, Tan(90°) = undefined, Tan(180°) = 0, Tan(270°) = undefined, Tan(360°) = 0
  • Tan(30°) = √3/3, Tan(45°) = 1, Tan(60°) = √3, Tan(120°) = -√3, Tan(135°) = -1, Tan(150°) = -√3/3
  • Cos(30°) = √3 / 2, Cos(45°) = √2 / 2, Cos(60°) = 1 / 2, Cos(120°) = -1 / 2, Cos(135°) = -√2 / 2, Cos(150°) = -√3 / 2
  • Sin(30°) = 0.5, Sin(45°) = √2 / 2, Sin(60°) = √3 / 2, Sin(120°) = √3 / 2, Sin(135°) = √2 / 2, Sin(150°) = 0.5

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Test your knowledge of trigonometric functions values for various angles. Identify the correct values for sine, cosine, and tangent for different angles between 0° and 360°.

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