Triangle Congruence: SAS Flashcards
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Questions and Answers

What is the missing statement in the proof that ΔACB ≅ ΔECD, given that AE and DB bisect each other at C?

∠ACB ≅ ∠ECD

Which of these triangle pairs can be mapped to each other using a single translation?

  • Triangle Pair A
  • Triangle Pair C
  • Triangle Pair D (correct)
  • Triangle Pair B

What is the second transformation used to map ΔHJK to ΔLMN after the translation of vertex H to vertex L?

a rotation about point H

Which of these triangle pairs can be mapped to each other using a single reflection?

<p>Triangle Pair A (D)</p> Signup and view all the answers

Which of these triangle pairs can be mapped to each other using both a translation and a reflection across the line containing AB?

<p>Triangle Pair D (D)</p> Signup and view all the answers

What additional information is needed to show ΔJKL ≅ ΔMNR by SAS, given that KL ≅ NR and JL ≅ MR?

<p>∠L ≅ ∠R</p> Signup and view all the answers

What is the missing statement in the proof that ΔEFG ≅ ΔJHG, given that G is the midpoint of HF, EF ∥ HJ, and EF ≅ HJ?

<p>∠GFE ≅ ∠GHJ</p> Signup and view all the answers

Can it be concluded that ΔRQS ≅ ΔNTV by SAS? Why or why not?

<p>No, it is not possible for the triangles to be congruent.</p> Signup and view all the answers

Segments _______ are therefore congruent by the definition of bisector.

<p>MS and QS</p> Signup and view all the answers

Which rigid transformation would map ΔAQR to ΔAKP?

<p>a rotation about point A</p> Signup and view all the answers

Flashcards

ΔACB ≅ ΔECD, bisecting segments

If segments AE and DB bisect each other at C, then ∠ACB ≅ ∠ECD.

Single translation mapping of triangles.

Triangle pair that can be mapped to each other using a single translation.

Triangle mapping: transformation after translation

The second transformation to map ΔHJK to ΔLMN after translating vertex H to vertex L is a rotation.

Single reflection mapping triangles

Triangle pair that can be mapped to each other using a single reflection.

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Translation and reflection mapping of triangles

Triangle pair that can be mapped to each other using a translation and a reflection across line AB

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SAS congruence missing info

To show ΔJKL ≅ ΔMNR by SAS, we need ∠L ≅ ∠R, given KL ≅ NR and JL ≅ MR.

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ΔEFG ≅ ΔJHG, missing statement

If G is the midpoint of HF, EF ∥ HJ, and EF ≅ HJ, then ∠GFE ≅ ∠GHJ.

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ΔRQS ≅ ΔNTV by SAS?

No, ΔRQS ≅ ΔNTV by SAS cannot be concluded because not enough information is given for the triangles to be congruent..

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Congruent segments (bisector)

MS and QS are congruent by the definition of bisector

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Triangle mapping: Rigid transformation

A rotation about point A maps ΔAQR to ΔAKP.

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Study Notes

Triangle Congruence: SAS

  • ΔACB ≅ ΔECD requires missing statement: ∠ACB ≅ ∠ECD for proof.
  • Identification of triangle pairs that can undergo a single translation, specifically D.
  • Mapping ΔHJK to ΔLMN involves two rigid transformations; first is translation from H to L, second is a rotation about point H.
  • Determination of triangle pairs that can be mapped using a single reflection indicates pair A.
  • Analysis reveals that pair D cannot be mapped through both translation and reflection across line AB.
  • To show ΔJKL ≅ ΔMNR by SAS with given KL ≅ NR and JL ≅ MR, additional requirement is ∠L ≅ ∠R.
  • For congruence of ΔEFG and ΔJHG, missing proof component is ∠GFE ≅ ∠GHJ, stated within the isosceles context.
  • Triangles RQS and NTV have right angles at ∠Q and ∠T respectively, but due to lacking necessary congruence, ΔRQS ≅ ΔNTV cannot be concluded by SAS.
  • Proof context of isosceles triangle ΔMNQ highlights base angles’ congruence; segments MS and QS must be congruent due to bisector definition.
  • Rigid transformation mapping ΔAQR to ΔAKP requires a rotation about point A for accurate congruence alignment.

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Test your understanding of triangle congruence with these flashcards focusing on the Side-Angle-Side (SAS) theorem. Each card presents a challenge related to triangle proofs and transformations. Perfect for reinforcing concepts in geometry.

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