Transition Metals: Properties and Trends
41 Questions
0 Views

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to Lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

Which of the following properties is NOT generally associated with transition elements?

  • Metallic lustre
  • High thermal conductivity
  • Low tensile strength (correct)
  • High malleability

Why do transition metals, excluding Zn, Cd, and Hg, typically exhibit high melting and boiling points?

  • Because only _ns_ electrons participate in metallic bonding
  • Due to weak interatomic interactions
  • Due to the involvement of both _(n-1)d_ and _ns_ electrons in metallic bonding (correct)
  • Because they have a small number of unpaired electrons

In a series of d-block elements, what factor primarily influences the rise in melting points to a maximum, such as observed with Chromium (Cr), Molybdenum (Mo), and Tungsten (W)?

  • Decreasing atomic radii
  • Increasing number of paired electrons
  • Decreasing atomic number
  • Large number of unpaired electrons that promote strong interatomic interaction (correct)

How does a metal's enthalpy of atomisation relate to its reactivity?

<p>Metals with very high enthalpies of atomisation tend to be less reactive. (B)</p> Signup and view all the answers

The second and third transition metal series generally exhibit greater enthalpies of atomisation compared to the first transition metal series. What is the primary reason for this difference?

<p>Greater effective nuclear charge and more extensive metallic bonding in the heavier series. (B)</p> Signup and view all the answers

Consider the electronic configurations provided in the table. Which element is MOST likely to exhibit the strongest metallic bonding?

<p>Chromium (Cr) (B)</p> Signup and view all the answers

Based on the trends in physical properties, which element from the provided data would you expect to have the HIGHEST boiling point?

<p>Tungsten (W) (A)</p> Signup and view all the answers

Interstitial compounds involving transition metals exhibit which combination of properties?

<p>High melting points, extreme hardness, and retention of metallic conductivity. (A)</p> Signup and view all the answers

Why are transition metals able to readily form alloys?

<p>Their similar atomic radii allow atoms to substitute within the crystal lattice. (B)</p> Signup and view all the answers

Which statement accurately describes the disproportionation of an oxidation state?

<p>A particular oxidation state becomes less stable, leading to simultaneous oxidation and reduction. (A)</p> Signup and view all the answers

How does the acidity of a metal oxide relate to the oxidation state of the metal?

<p>Higher oxidation states result in more acidic oxides. (B)</p> Signup and view all the answers

How does changing the pH of a solution affect the equilibrium between chromate ($\text{CrO}_4^{2-}$) and dichromate ($\text{Cr}_2\text{O}_7^{2-}$) ions?

<p>Increasing pH favors the formation of chromate ions. (D)</p> Signup and view all the answers

The standard electrode potential, $E^0 _{M^{2+}/M}$, for $Mn$, $Ni$, and $Zn$ is more negative than expected. Which factor primarily contributes to this?

<p>The extra stability of half-filled d-orbital in $Mn^{2+}$ leading to low overall ionization enthalpy. (A)</p> Signup and view all the answers

A low (negative) $E^0 (M^{3+}/M^{2+})$ value is observed for Scandium ($Sc$). What accounts for this observation?

<p>The attainment of a stable noble gas configuration by $Sc^{3+}$ . (B)</p> Signup and view all the answers

Zinc ($Zn$) exhibits the highest $E^0 (M^{3+}/M^{2+})$ value among the first-row transition metals. Which statement best explains this?

<p>The difficulty in removing a third electron from the stable $d^{10}$ configuration in $Zn^{2+}$. (D)</p> Signup and view all the answers

Manganese ($Mn$) has a comparatively high $E^0 (M^{3+}/M^{2+})$ value. What is the primary reason for this?

<p>The extra stability of $Mn^{2+}$ with its $d^5$ configuration. (A)</p> Signup and view all the answers

Iron ($Fe$) exhibits a low $E^0 (M^{3+}/M^{2+})$ value. Which of the following factors contributes most to this?

<p>The extra stability of $Fe^{3+}$ due to its $d^5$ configuration. (B)</p> Signup and view all the answers

Vanadium ($V$) has a comparatively high $E^0 (M^{3+}/M^{2+})$ value. What is the main reason behind this observation?

<p>The stability of $V^{2+}$ with a half-filled $t_{2g}$ level configuration. (C)</p> Signup and view all the answers

Titanium ($Ti$) achieves its highest oxidation state in $TiX_4$ compounds. What property of fluorine enables this?

<p>Fluorine's high electronegativity, which forces titanium to achieve its highest oxidation state. (A)</p> Signup and view all the answers

Why are the contributions of orbital angular momentum considered insignificant for compounds containing first-series transition metals?

<p>The orbital angular momentum is effectively quenched. (A)</p> Signup and view all the answers

While $CoF_3$ exists, $CuI_2$ does not. What explains the instability of $CuI_2$?

<p>$Cu^{2+}$ oxidizes $I^−$ to $I_2$, leading to the formation of $Cu_2I_2$ and $I_2$. (D)</p> Signup and view all the answers

Transition metals tend to form their highest oxidation states in oxides and fluorides, but not typically in other halides. Why?

<p>Oxygen and fluorine are highly electronegative, thus stabilizing higher oxidation states. (B)</p> Signup and view all the answers

Which of the following is NOT a characteristic property exhibited by transition elements?

<p>Formation of crystalline structures with high symmetry (D)</p> Signup and view all the answers

The color observed in transition metal complexes typically arises due to what phenomenon?

<p>Absorption of light leading to $d-d$ transitions (A)</p> Signup and view all the answers

Which factor is NOT a primary reason for transition metals' ability to form complex compounds?

<p>Their low electronegativity values (D)</p> Signup and view all the answers

Why do transition metal ions often exhibit catalytic activity?

<p>Due to their ability to adopt multiple oxidation states (D)</p> Signup and view all the answers

What role do transition metals play in increasing reactant concentration on a catalyst surface?

<p>They facilitate reactant adsorption, increasing local concentration (B)</p> Signup and view all the answers

What is the primary characteristic of interstitial compounds related to their stoichiometry?

<p>They are usually non-stoichiometric. (D)</p> Signup and view all the answers

Which characteristic is least likely to be associated with interstitial compounds?

<p>Complete solubility in polar solvents (C)</p> Signup and view all the answers

How does the presence of incompletely filled $d$ orbitals contribute to the catalytic activity of transition metals?

<p>By providing a pathway for electron transfer and complex formation (C)</p> Signup and view all the answers

How does the ability of transition metals to lower activation energy contribute to their catalytic activity?

<p>By stabilizing the transition state of the reaction (C)</p> Signup and view all the answers

Why does oxygen stabilize higher oxidation states of transition metals more effectively than fluorine?

<p>Oxygen can form multiple bonds with metals, enabling it to accommodate higher charge densities. (D)</p> Signup and view all the answers

In the context of the first transition series, what is the primary reason for the trend of $E^0$ values for $M^{2+}/M$ becoming less negative across the series?

<p>An increase in the sum of the first and second ionization enthalpies. (B)</p> Signup and view all the answers

Why are $Mn^{3+}$ and $Co^{3+}$ ions considered strong oxidizing agents in aqueous solutions?

<p>They can easily be reduced to $Mn^{2+}$ and $Co^{2+}$, which are more stable oxidation states. (A)</p> Signup and view all the answers

Why are $Ti^{2+}, V^{2+}$, and $Cr^{2+}$ strong reducing agents that can liberate hydrogen from dilute acids?

<p>They are oxidized to form stable electronic configurations such as $Ti^{4+}, V^{5+}$, and $Cr^{3+}$. (A)</p> Signup and view all the answers

Which of the following best describes the origin of paramagnetism in transition metal ions?

<p>The presence of unpaired electrons, each possessing a magnetic moment due to spin and orbital angular momentum. (C)</p> Signup and view all the answers

What distinguishes ferromagnetism from paramagnetism?

<p>Ferromagnetism involves strong alignment of electron spins, leading to a much stronger attraction to magnetic fields. (D)</p> Signup and view all the answers

Why do titanium and vanadium exhibit passivity towards dilute non-oxidizing acids at room temperature?

<p>They form a protective oxide layer on their surface that prevents further reaction. (B)</p> Signup and view all the answers

In $Mn_2O_7$, what is the structural arrangement around each manganese atom?

<p>Each Mn is tetrahedrally surrounded by four oxygen atoms. (D)</p> Signup and view all the answers

Which of the following statements accurately describes the oxide formation trend across the first-row transition metals?

<p>The highest oxidation number in the oxides coincides with the group number up to manganese ($Mn_2O_7$). (A)</p> Signup and view all the answers

What is the role of oxocations like $VO_2^+$, $VO^{2+}$, and $TiO^{2+}$ in stabilizing certain oxidation states of transition metals?

<p>They stabilize the metal in a complex, influencing the redox behavior of the metal. (C)</p> Signup and view all the answers

Flashcards

Transition Elements Properties

Elements in the d-block that exhibit metallic properties, tensile strength, ductility, malleability, thermal and electrical conductivity, and luster.

High Melting Points of Transition Metals

Transition metals have low volatility, high hardness, high melting and boiling points, and high enthalpy of atomization due to the involvement of (n-1)d and ns electrons in metallic bonding.

Melting Point Trends in d-block

Melting points increase to a maximum at Cr, Mo, and W in a row of d-block elements, then decrease due to the relationship between unpaired electrons and interatomic interaction.

Enthalpy of Atomization and Reactivity

Enthalpy of atomization influences a metal's standard electrode potential; high enthalpy means the metal is less reactive and will acts as noble metal.

Signup and view all the flashcards

Enthalpies of Atomization Trends

Second and third transition metal series have greater enthalpies than the first series due to stronger metallic bonding.

Signup and view all the flashcards

Electronic Configuration of Chromium (Cr)

Electronic configuration of Cr is [Ar] 3d⁵ 4s¹, not [Ar] 3d⁴ 4s² because a half-filled d-orbital leads to higher stability due to exchange energy.

Signup and view all the flashcards

Electronic Configuration of Copper (Cu)

Electronic configuration should be [Ar] 3d¹⁰ 4s¹, not [Ar] 3d⁹ 4s², due to the stability of a fully filled d-orbital.

Signup and view all the flashcards

Interstitial Compounds

Compounds formed when small atoms (like B, C, N) occupy voids in a transition metal's crystal lattice.

Signup and view all the flashcards

Alloy Formation (Solid Solution)

A homogeneous solid solution where atoms of one metal are randomly distributed among the atoms of another.

Signup and view all the flashcards

Disproportionation Reaction

When a particular oxidation state becomes less stable, resulting in the formation of both a lower and a higher oxidation state.

Signup and view all the flashcards

Chromate-Dichromate Equilibrium

Chromates (CrO₄²⁻) and dichromates (Cr₂O₇²⁻) are interconvertible in aqueous solution, and their equilibrium depends on pH.

Signup and view all the flashcards

Potassium Dichromate (K₂Cr₂O₇) Preparation

Prepared from chromite ore (FeCr₂O₄) through fusion with an oxidizing agent. Used in leather industry and as an oxidant.

Signup and view all the flashcards

Oxygen's Bonding Ability

Oxygen can form multiple bonds to metals, allowing it to stabilize higher oxidation states better than fluorine and form bridging structures like Mn-O-Mn.

Signup and view all the flashcards

Oxidation Number and Group Number

In some compounds, the highest oxidation number in the oxides matches the group number, like $Sc_2O_3$ to $Mn_2O_7$.

Signup and view all the flashcards

Oxide Formation Beyond Group 7

After Group 7, elements like iron do not form higher oxides above $Fe_2O_3$. Instead, they form ferrates in alkaline conditions, which decompose into $Fe_2O_3$ and $O_2$.

Signup and view all the flashcards

Reactivity of First-Row Metals

Many transition metals like titanium and vanadium are more reactive than copper. Although the rate at which the metals reacts with oxidising agents like hydrogen ion ($H^+$) can sometimes be slow.

Signup and view all the flashcards

$E^0$ Trends Across the Series

$E^0$ values for $M^{2+}/M$ become less negative going across the first transition series due to increasing ionization enthalpies making conversion of M to $M^{2+}$ more difficult.

Signup and view all the flashcards

Strong Oxidizing Agents

$Mn^{3+}$ and $Co^{3+}$ ions are strong oxidizing agents in aqueous solutions because they readily undergo reduction to more stable $Mn^{2+}$ and $Co^{2+}$ ions.

Signup and view all the flashcards

Strong Reducing Agents

Ions like $Ti^{2+}, V^{2+}, and Cr^{2+}$ are strong reducing agents because they are easily oxidized to more stable configurations such as $Ti^{4+}, V^{5+}, and Cr^{3+}.

Signup and view all the flashcards

Diamagnetism

Diamagnetic substances are repelled by magnetic fields.

Signup and view all the flashcards

Paramagnetism

Paramagnetic substances are attracted to magnetic fields due to unpaired electrons.

Signup and view all the flashcards

Ferromagnetism

Ferromagnetism is a very strong attraction to magnetic fields being an extreme form of paramagnetism.

Signup and view all the flashcards

Unexpected $E^0 _{M^{2+}/M}$ for Mn, Ni, Zn

Mn, Ni, and Zn have more negative $E^0 _{M^{2+}/M}$ values due to half-filled d orbital stability (Mn) or stable full d orbitals (Zn).

Signup and view all the flashcards

Low $E^0 (M^{3+}/M^{2+})$ for Sc

Sc3+ is very stable because it has a noble gas configuration ($[Ar]_{18}4s^03d^0$).

Signup and view all the flashcards

High $E^0 (M^{3+}/M^{2+})$ for Zn

Removing a third electron from the stable $d^{10}$ configuration of $Zn^{2+}$ requires a lot of energy.

Signup and view all the flashcards

High $E^0 (M^{3+}/M^{2+})$ for Mn

Mn2+ ($d^5$) is particularly stable, so converting it to Mn3+ requires more energy.

Signup and view all the flashcards

Low $E^0 (M^{3+}/M^{2+})$ for Fe

Fe$^{3+}$ ($d^5$) has extra stability, which is why less energy is needed to convert $Fe^{2+}$ to $Fe^{3+}$.

Signup and view all the flashcards

Fluorine Stabilizes High Oxidation States

Fluorine is highly electronegative and small, thus can stabilize high oxidation states through high lattice energy (ionic compounds) or high bond enthalpy (covalent compounds).

Signup and view all the flashcards

Why is $CoF_3$ known?

The ability of fluorine to stabilise the highest oxidation state is due to higher lattice energy as in the case of $CoF_3$

Signup and view all the flashcards

Why are $VF_5$ and $CrF_6$ known?

The ability of fluorine to stabilise the highest oxidation state is due to higher bond enthalpy terms for the higher covalent compounds, e.g., $VF_5$ and $CrF_6$.

Signup and view all the flashcards

Transition elements form its highest oxidation states in its oxides and not fluorides.Why?

Transition elements form its highest oxidation states in its oxides because oxygen is highly electronegative and forces the metal to enter into tis highest oxidation states and the ability of oxygen to stabilise the highest oxidation state is demonstrated in the oxides.

Signup and view all the flashcards

Colored Transition Metal Compounds

Colored compounds due to d-d transitions absorbing visible light and radiating complementary colors.

Signup and view all the flashcards

Complex Compounds

Species where metal ions bind anions or neutral molecules.

Signup and view all the flashcards

Catalytic Activity

Ability to accelerate reactions by providing a surface or intermediate for the reaction.

Signup and view all the flashcards

Alloys

Mixtures of metals with enhanced properties.

Signup and view all the flashcards

d-d Transitions

Energy matches frequency of absorbed light, exciting electrons to higher energy d orbitals.

Signup and view all the flashcards

Why Transition Metals Form Complexes

Smaller size, high ionic charges, and available d orbitals.

Signup and view all the flashcards

Multiple Oxidation States in Catalysis

Ability to adopt multiple oxidation states, facilitating electron transfer.

Signup and view all the flashcards

Variable Oxidation States Enhance Catalysis

Transition metals change oxidation states, becoming effective catalysts.

Signup and view all the flashcards

Properties of Interstitial Compounds

Non-stoichiometric, hard, chemically inert with high melting points.

Signup and view all the flashcards

Study Notes

  • D-block elements are in groups 3-12 of the periodic table.
  • D orbitals are progressively filled in the four long periods.
  • The d-orbitals of the penultimate energy level receive electrons.
  • This gives rise to the three rows of the transition metals (3d, 4d, and 5d series).
  • The general electronic configuration is (n-1)d¹⁻¹⁰ns¹⁻².
  • "(n-1)" stands for the inner d orbitals, which may have 1-10 electrons, in the outermost ns orbital.
  • It may have one or two electrons.
  • Transition elements have three main series; 3d, 4d, and 5d.
  • 3d series includes elements Sc to Zn.
  • 4d includes Y to Cd.
  • 5d series includes La to Hg, except Ce to Lu.
  • A 6d series starts from Ac to Cn (Copernicium), except Thorium to Lawrencium

d Orbital Properties

  • Electrons in d-orbitals project to the periphery of an atom.
  • The d-orbitals are more influenced by the surroundings.
  • They affect surrounding atoms or molecules.
  • Partly filled d orbitals show a variety of oxidation states e.g. +2, +3.
  • They form coloured ions (d-d transition).
  • They enter into complex formation with a variety of ligands.
  • Transition metals and compounds exhibit catalytic property and paramagnetic behavior.
  • There are greater horizontal similarities in transition elements.
  • This is in contrast to the main group elements.
  • All transition elements contain an incompletely filled d-subshell, while the outer shell electronic configuration remains the same.

f-Block Element Properties

  • F-block elements are those in which the 4f and 5f orbitals are progressively filled.
  • They're taken from group 3 of the periodic table to form a separate f-block.
  • F block elements are known as inner transition metals.
  • The two series of inner transition metals, (4f and 5f) are called lanthanoids and actinoids, respectively.
  • The f-block consists of the two series: lanthanoids (the fourteen elements following lanthanum) and actinoids (the fourteen elements following actinium).

Lanthanoids

  • Lanthanum closely resembles the lanthanoids.
  • It is included in discussions of the lanthanoids, signified by the general symbol Ln.
  • The discussion of the actinoids includes actinium besides the fourteen elements constituting the series.
  • The general electronic configurations is ns² (n-1)d⁰⁻¹ (n-2)f¹⁻¹⁴.
  • A transition element is defined as one which has incompletely filled d orbitals in its ground state or any one of its oxidation states.

Transition Metals

  • Zinc, cadmium, and mercury of group 12 have full d¹⁰ configurations in their ground state.
  • They also have the same configurations in common oxidation states.
  • They are not regarded as transition metals.
  • The electronic configurations of Zn, Cd, and Hg are represented by the general formula (n-1)d¹⁰ns².
  • Being the end members of the three transition series, the chemistry of Zinc, cadmium, and mercury studied along with the chemistry of the transition metals.
  • The d-block occupies the large middle section flanked by "s" and "p" blocks in the periodic table.
  • "Transition" is due to the position between s- (highly metallic elements) and p– block elements (mainly non-metals).
  • The change between metallic and non-metallic character takes place through this series.

Electronic Configuration

  • The electronic configuration of Cr in the 3d series, has 3d⁵4s¹ instead of 3d⁴4s².
  • The energy gap between the two sets (3d and 4s) of orbitals decreases and stability is better

Series Configurations

  • 1-series: Sc, Ti, V, Cr, Mn, Fe, Co, Ni, Cu, Zn
  • Atomic No-Z: 21, 22, 23, 24, 25, 26, 27, 28, 29, 30
  • 4s: 2, 2, 2, 1, 2, 2, 2, 2, 1, 2
  • 3d: 1, 2, 3, 5, 5, 6, 7, 8, 10, 10
  • 2-series: Y, Zr, Nb, Mo, Tc, Ru, Rh, Pd, Ag, Cd
  • Atomic No-Z: 39, 40, 41, 42, 43, 44, 45, 46, 47, 48
  • 5s: 2, 2, 2, 1, 1, 1, 1, 0, 1, 2
  • 4d: 1, 2, 4, 5, 6, 7, 8, 10, 10, 10
  • 3-series: La, Hf, Ta, W, Re, Os, Ir, Pt, Au, Hg
  • Atomic No-Z: 57, 72, 73, 74, 75, 76, 77, 78, 79, 80
  • 6s: 2, 2, 2, 2, 2, 2, 2, 1, 1, 2
  • 5d: 1, 2, 3, 4, 5, 6, 7, 8, 10, 10
  • 4 series: Ac, Rf, Db, Sg, Bh, Hs, Mt, Ds, Rg, Uub
  • Atomic No-Z: 89, 106, 105, 104, 103, 102, 101, 100, 99, 98
  • 7s: 2, 2, 2, 2, 2, 2, 2, 2, 1, 2
  • 6d: 1, 2, 3, 4, 5, 6, 7, 8, 10, 10

Metallic element properties

  • Transition elements display metallic properties, such as high tensile strength, ductility, malleability, high thermal and electrical conductivity, and metallic luster.
  • Zn, Cd, Hg and Mn are exceptions.
  • Most transition elements have one or more typical metallic structures at normal temperatures.
  • Transition elements have low volatility due to high atomization enthalpy; and very high melting and boiling points.
  • The high melting points of these metals are attributed to the involvement of greater number of electrons from (n-1)d in addition to the ns electrons in the interatomic metallic bonding.
  • A large number of unpaired electrons is favorable for strong interatomic interaction.
  • In a row of d block elements, Cr, Mo, W has maximum melting points. Due to unpaired electrons being favorable for strong inter atomic interaction
  • Enthalpy of atomization determines the standard electrode potential of a metal.
  • Metals with very high enthalpy of atomization (i.e., very high boiling point) tend to be noble in their reactions (less reactive).
  • The metals of more frequent series have greater enthalpies of metal – metal bonding in compounds of the heavy transition metals
  • This is in turn is due to involvement of electrons of ns and (n-1)d orbital as they are held less strongly by the nucleus as atomic size increases down the group.

Varying Atomic Properties

  • Ions of the same charge decrease in radius with increasing atomic number.
  • This is because the new electron enters a d orbital each time the nuclear charge increases by unity. Shielding is not that effective
  • The radii of the third (5d) series are similar to the second (4d) series.
  • Phenomenon with Lanthanoid contraction compensating for expected increase in atomic size.
  • The steady decrease in atomic and ionic size of lanthanide elements with increasing atomic no due to poor shielding of 4f electrons is called lanthanoid contraction.
  • Consequences of lanthanoid contraction:
    • second and third d series exhibit similar radii (e.g., Zr 160 pm, Hf 159 pm)
    • have very similar physical and chemical properties more than that expected
    • results in their joint occurrence in nature
    • difficulty in separation.
  • It is difficult to separate lanthanoid elements due to similar chemical properties.
  • Basicity decreases from La(OH)3 to Lu(OH)3 due to the decrease in metallic radius coupled with increase in atomic mass, resulting in a general increase in the density of these elements. (density = mass /volume).
  • From titanium (Z = 22) to copper (Z = 29), there is a significant increase in the density.
  • Atomic radii increase towards the end of each series because d and s subshells are completely filled due to electron electron repulsion, thus increasing their radii.

Ionization Enthalpies

  • Nuclear charge leads to rise in ionization enthalpy along each series of the transition elements from left to right.
  • The first ionization enthalpy increases as the effective nuclear charge increases.
  • The value of first ionization enthalpy may be lower for Cr because of the absence of any change in the d configuration.
  • The value for Zn may be higher because it represents ionization from the 4s level.
  • Elements do not increase as steeply.
  • The removal of one electron alters the relative energies of 4s and 3d orbitalsSo the dipositive ions have a configurations with no 4s electrons. -Reorganization occurs with some gains in exchange energy as number of d electrons increases
  • Irregular trend in first ionisation of 3d metals
  • Unusual extra stability of d, d half filled t2g stability
  • The lowest common oxidation state of 3d series metals is +2, except Cu with +1.
  • M2+ ions require the sum of the first and second ionisation energies in addition to the enthalpy of atomisation for each element.
  • Second ionisation has high values for Cr and Cu
  • disruption causes considerable loss of exchange energy with Presence of half filled and completely filled d orbital cause second ionization
  • As the ionisation consists of the removal of an electron which allows the production of the stable d¹⁰ configuration. [Ar]184s⁰3d¹⁰
  • The trend in the third ionisation enthalpies is high
  • Greater difficulty of removing an electron from ½ filled and do completely
  • The lowest common oxidation state of 3d series metals is +2, except Cu with +1.

Variable Oxidation States of Transition Elements

  • Both ns and (n-1) d electrons are involved in the bonding as there is no much energy difference between them.
  • The elements which give the greatest number of oxidation states occur in or near the middle of the series i.e. Manganese for example
  • The difference in oxidation in transition elements increases by unity and in non transition elements they normally increase by a unity of two. The variability in the oxidation of transition states comes from the incomplete filling of d orbitals whereas . In the d-block, the higher oxidation states are favored by the heavier members. In the p-block, the tower oxidation states are favored by heavier members (due to inert pair effects)-. Low oxidation states occur w complex compound with ligands

Oxidation

  • Titanium (IV) is more stable [Ar] 184s°3d° (noble gas configuration).
  • The only oxidation state of zinc is +2 (no d electrons are involved).
  • [Ar]184s°3d¹⁰ (completely filled d orbital stability) Mn [Ar] 184s²3d³
  • The electron is removed from stable s orbital with complete filling
  • Mn¹+ does not exist because first ionization enthalpy is very high.
  • +2 oxidation stability because 2nd IE is compartively lower

Electrode Potentials

  • The high energy to transform Cu(s) to Cu²+(aq) is not balanced by its hydration enthalpy.
  • Hydration enthalpy of Cu²+(aq) is not sufficient to provide very high atomization and first two ionization enthalpy of Cu- Having a positive Ecu²+/Cu accounts for its inability to liberate H₂ from acids.
  • Hydrogen is more reactive than Cu- Only oxidising acids (nitric and hot concentrated sulphuric) react with Cu
  • The general trend towards less negative E° ²+/M values(less tendancy to undergo oxidation)
  • Across the series is related to the general increase in the sum of the first and second ionisation enthalpies
  • Mn²+ + oxdises to Mn2+ low sum of first two IE
  • Ni ger oxidixsed + negative

Metal Oxidation

  • Low E (M³+/M²+) (negative value) for Sc reflects the stability of Se³+ config.
  • The highest value E (M³+/M²+) for Zn is due to the from the stable d¹⁰ difficult

Properties

  • Diamagnetic substances are repelled by the applied field while
  • the paramagnetic substances are attracted
  • Substances which are attracted very strongly are said to be ferromagnetic.
  • Extreme form of paramagnetism
  • unpaird e- = magnetic movement

Unpaired electrons

Transition elements show interstitial compounds (H,C, or N in metal crystal lattices) are usually :

  • non stoichiometric
  • non ionic/covalent These compounds have:
  1. high melting points 2)some borides approach diamond in hardness
  2. retain metallic conductivity 4)re chemically inert

Alloys

Alloys may be homogeneous solid solutions. One metal is distributed randomly among the atoms of the other.

  • atoms must be are within about 15% of each other.
  • Alloys are hard/high melting points. Metals can replace one another in the crystal lattice.

Disproportionation of Oxidation States:

  1. a particular oxidation state becomes less stable relative to other oxidation state, one lower,
  2. said to undergo disproportionation. For example, manganese (VI) becomes unstable relative to (VII)

Oxide Properties

Oxoanion Mn2O7: Covalent green oil - higher oxides Gives HMnO4 (acidic properties predominates). V2O5: amphoteric though mainly acidic (VO salts with alkalies and VO salts with acids ) V2O3, CrO: Basic V2O4:Less basic

Potassium Dichromate

Potassium dichromate is a important Industry and also an oxidant Generally prepared Chromite Ore Yellow solution -orange sodium. CrO42 is tetrahedral 2 crO42 (high pH) 2Cr4 +2H->Cr,3 + 2H (low pH)

More on Oxidizing Action

Sodium/potassium Oxidizing agent:

  • in organic chemistry
  • in acidic solution Cr2O7 * 14H* * 6e" ->2Cr2+ + 7HO 1 Potassium permanganate forms dark purple (almost black) crystals which are isostructural with those of KClO4, 1 The salt is not very soluble in water but when heated it decomposes at 513 К: 2KMnO4 K2MnO4+MNO2+2 Oxidising action of Acidify :

Inner Transition Elements

Only one oxidation La(III) and L(III) pounds Actinide chemistry's more complicated Awide range of oxidation Lanthanoids

  • Atomic Sizes decreases from left to right This happens more than Irregularity (as in ionization enthalpies) arises mainly from the extra stability First ionisation enthalpies of the lanthanoids Lanthanoids the exchange enthalpy considerations

Studying That Suits You

Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

Quiz Team

Related Documents

Description

Explore the distinctive properties of transition metals, including melting and boiling points, enthalpies of atomisation, and metallic bonding. Understand the factors influencing these properties across the d-block elements, like electronic configurations.

More Like This

Use Quizgecko on...
Browser
Browser