Traffic Engineering: Holding Time and Traffic Intensity

The probability of finding the trunk ______ is equal to the proportion of time for which the trunk is busy.

Traffic intensity is measured in ______.

A single trunk (CCS) cannot carry more than one ______, i.e., 𝐴 ≤ 1 for one trunk.

The ______ Hour is the hour that has the most number of calls.

The Busy Hour depends on various factors such as ______, weather and international events.

Traffic intensity = (25+15+18+12)/______ = 1.2 E.

The average number of calls in progress during a time T with holding time h is called ______ intensity.

The duration of a call is called its ______ time because it holds the trunk for that time.

The probability of a call lasting at least t sec is given by 𝑃 𝑡 =𝑒 𝑛 𝑇 − 𝑡 ℎ where t/h is the average ______ time.

1 ______ represents that circuit occupied for 1-hour, i.e., circuit occupied for entire observation.

The maximum capacity of single server is ______ E.

The number of calls in progress at different intervals of time for a day is represented by ______.

The waiting time is dependent on the following factors: 1) Number of ______ 2) Number of servers

The service depends on two factors: 1) Waiting ______ are selected in first-in first serviced FCFS or FIFO

Under heavy traffic, ______ occurs

Probability of waiting (the probability of finding all lines occupied) is equal to ______ > 0 = 𝐶(𝑁, 𝐴) N-1

B = ______ probability for a LCC system

For single server systems (N = 1), the probability of delay = ρ, i.e. ______ utilization or traffic carried by the server

Assume that call arrivals are ______ and service time is negative exponential distribution.

The average delay of a call is 𝜇𝑘 = ቊ ______ 𝜇, 𝑘 = 0,1, …, 𝑁.

The probability of delay P > t is equal to P(> 0) e^(- ______ t/T_h)

When n = ∞, the above equation reduces to ______’s Delay formula.

The average waiting time for all arrivals is W_t_avg = ______ N, A h / (N-A)

When n = N, the above equation reduces to ______’s – B formula.

The probability of ______ is given by the formula 𝑃(𝑘) = 𝜆0 𝜆1 …..𝜆𝑘−1 𝑃(0).

The average delay of only those arrivals that get delayed is T_W = h / ______ - A

The average service time is given by h = 1 / ______ of the negative exponential service time distribution

The probability of delay P(delay) = P(> 0) = ______ = 0.9

The average waiting time W_t_avg is given by ______ N, A h / (N-A) for a message switching network