Thevenin's Theorem Quiz

The equivalent resistance of the circuit is $6.67 \Omega$.

The equivalent resistance is calculated by finding the parallel resistance of the 10 $\Omega$ and 20 $\Omega$ resistors.

The calculated current in the circuit is 0.33 A.

The voltage drop across both resistors is 13.33 V.

The purpose of drawing Thevenin’s equivalent circuit is to simplify the original circuit to a single voltage source and a single resistor.

The equivalent resistance of the circuit is calculated as follows: $R_{eq} = \frac{R_1 \cdot R_2},{R_1 + R_2}$, where $R_1$ and $R_2$ are the resistances of the parallel resistors.

The current flowing around the loop can be calculated using Ohm's law: $I = \frac{V_{AB}},{R_{eq}}$, where $V_{AB}$ is the voltage across the equivalent resistance and $R_{eq}$ is the equivalent resistance of the circuit.

The voltage drop across the resistors is significant because it helps determine the voltage distribution within the circuit and ensures that Kirchhoff's voltage law is satisfied.

The process involves representing the circuit with a single voltage source and a single series resistance, where the voltage source is equal to the voltage across the load resistance and the series resistance is equal to the equivalent resistance of the circuit.

The Thevenin’s equivalent circuit helps simplify complex circuits by replacing them with a simplified circuit model, making it easier to analyze and solve for circuit parameters.