Thevenin's Theorem Quiz

The equivalent resistance of the circuit is $6.67 \Omega$.

The equivalent resistance is calculated by finding the parallel resistance of the 10 $\Omega$ and 20 $\Omega$ resistors.

The calculated current in the circuit is 0.33 A.

<p>The voltage drop across both resistors is 13.33 V.</p> Signup and view all the answers

<p>The purpose of drawing Thevenin’s equivalent circuit is to simplify the original circuit to a single voltage source and a single resistor.</p> Signup and view all the answers

<p>The equivalent resistance of the circuit is calculated as follows: $R_{eq} = \frac{R_1 \cdot R_2},{R_1 + R_2}$, where $R_1$ and $R_2$ are the resistances of the parallel resistors.</p> Signup and view all the answers

<p>The current flowing around the loop can be calculated using Ohm's law: $I = \frac{V_{AB}},{R_{eq}}$, where $V_{AB}$ is the voltage across the equivalent resistance and $R_{eq}$ is the equivalent resistance of the circuit.</p> Signup and view all the answers

<p>The voltage drop across the resistors is significant because it helps determine the voltage distribution within the circuit and ensures that Kirchhoff's voltage law is satisfied.</p> Signup and view all the answers

<p>The process involves representing the circuit with a single voltage source and a single series resistance, where the voltage source is equal to the voltage across the load resistance and the series resistance is equal to the equivalent resistance of the circuit.</p> Signup and view all the answers

<p>The Thevenin’s equivalent circuit helps simplify complex circuits by replacing them with a simplified circuit model, making it easier to analyze and solve for circuit parameters.</p> Signup and view all the answers