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Thermodynamics and Thermochenistry Fundamentals
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Thermodynamics and Thermochenistry Fundamentals

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Questions and Answers

What is the purpose of the coffee cup calorimeter?

  • To measure the enthalpy change of a reaction.
  • To measure the heat of combustion of a substance.
  • To measure the heat transfer in a process open to the atmosphere. (correct)
  • To measure the heat capacity of a substance.
  • What is the primary difference between constant-pressure and constant-volume calorimetry?

  • One measures heat transfer, while the other measures heat capacity.
  • One is used for reactions at constant temperature, while the other is used for reactions at constant pressure.
  • One is used for open systems, while the other is used for closed systems. (correct)
  • One measures the heat of combustion, while the other measures the heat of reaction.
  • What is the formula for the heat transfer in a coffee cup calorimeter?

  • QH2O = Qsolid + msolidCsolid (Tfinal-Tinitial)solid
  • Qsolid = QH2O + msolidCsolid (Tfinal-Tinitial)solid (correct)
  • QH2O = Qsolid - msolidCsolid (Tfinal-Tinitial)solid
  • Qsolid = QH2O - msolidCsolid (Tfinal-Tinitial)solid
  • What is the specific heat of water in J/g°C?

    <p>4.184 J/g°C</p> Signup and view all the answers

    What is the purpose of a bomb calorimeter?

    <p>To measure the heat of combustion of a substance.</p> Signup and view all the answers

    What is the formula for the heat of reaction in a bomb calorimeter?

    <p>Qreaction = -(Qwater + Qcal)</p> Signup and view all the answers

    What is the heat capacity of the calorimeter in J/°C in the example problem?

    <p>890 J/°C</p> Signup and view all the answers

    What is the temperature increase of the water in the example problem?

    <p>9.0°C</p> Signup and view all the answers

    What is the purpose of the heat of reaction?

    <p>To measure the enthalpy change of a chemical reaction.</p> Signup and view all the answers

    What is the unit of the heat of combustion in the example problem?

    <p>kJ/mol</p> Signup and view all the answers

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