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Questions and Answers
In the balanced chemical equation $N_2 + 3H_2 \rightarrow 2NH_3$, if you have 6 moles of $H_2$, how many moles of $NH_3$ can be produced?
In the balanced chemical equation $N_2 + 3H_2 \rightarrow 2NH_3$, if you have 6 moles of $H_2$, how many moles of $NH_3$ can be produced?
- 2 moles
- 6 moles
- 4 moles (correct)
- 3 moles
Consider the reaction $2CO(g) + O_2(g) \rightarrow 2CO_2(g)$. If 4 moles of $CO$ and 3 moles of $O_2$ are initially present, which reactant is the limiting reactant?
Consider the reaction $2CO(g) + O_2(g) \rightarrow 2CO_2(g)$. If 4 moles of $CO$ and 3 moles of $O_2$ are initially present, which reactant is the limiting reactant?
- CO (correct)
- Neither, both will be consumed at the same rate.
- CO_2
- O_2
A compound is found to contain 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is its empirical formula?
A compound is found to contain 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is its empirical formula?
- $C_3H_8O$
- $CH_2O$ (correct)
- $CHO_2$
- $C_2H_4O_3$
If the actual yield of a reaction is 15 grams and the theoretical yield is 20 grams, what is the percent yield?
If the actual yield of a reaction is 15 grams and the theoretical yield is 20 grams, what is the percent yield?
How many grams of NaCl are present in 0.25 moles of NaCl? (Molar mass of NaCl = 58.44 g/mol)
How many grams of NaCl are present in 0.25 moles of NaCl? (Molar mass of NaCl = 58.44 g/mol)
What is the molar mass of $Ca(OH)_2$? (Molar mass of Ca = 40.08 g/mol, O = 16.00 g/mol, H = 1.008 g/mol)
What is the molar mass of $Ca(OH)_2$? (Molar mass of Ca = 40.08 g/mol, O = 16.00 g/mol, H = 1.008 g/mol)
If the empirical formula of a compound is $CH_2$ and its molar mass is 56 g/mol, what is its molecular formula?
If the empirical formula of a compound is $CH_2$ and its molar mass is 56 g/mol, what is its molecular formula?
In the reaction $A + 2B \rightarrow C$, if 1 mole of A reacts with 2 moles of B to produce 1 mole of C, what is the mole ratio of B to C?
In the reaction $A + 2B \rightarrow C$, if 1 mole of A reacts with 2 moles of B to produce 1 mole of C, what is the mole ratio of B to C?
How many molecules are there in 0.5 moles of $O_2$?
How many molecules are there in 0.5 moles of $O_2$?
What is the definition of the limiting reactant in a chemical reaction?
What is the definition of the limiting reactant in a chemical reaction?
Flashcards
What is a mole?
What is a mole?
The amount of substance, defined as exactly 6.02214076 × 10²³ elementary entities (Avogadro's number).
What is molar mass?
What is molar mass?
The mass of one mole of a substance, typically expressed in grams per mole (g/mol).
What is a balanced chemical equation?
What is a balanced chemical equation?
A balanced equation has the same number of atoms of each element on both sides.
What is a mole ratio?
What is a mole ratio?
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What is the limiting reactant?
What is the limiting reactant?
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What is theoretical yield?
What is theoretical yield?
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What is actual yield?
What is actual yield?
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What is percent yield?
What is percent yield?
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What is an empirical formula?
What is an empirical formula?
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What is the molecular formula?
What is the molecular formula?
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Study Notes
- The mole concept is a way of expressing the amount of a substance
- Stoichiometry deals with the quantitative relationships between reactants and products in chemical reactions
The Mole
- A mole (symbol: mol) is the base unit of amount of substance in the International System of Units (SI)
- It is defined as exactly 6.02214076 × 10²³ elementary entities
- This number is known as Avogadro's constant (NA)
- Elementary entities can be atoms, molecules, ions, or other specified particles
- One mole of any substance contains the same number of entities as there are atoms in 12 grams of carbon-12
Molar Mass
- Molar mass (M) is the mass of one mole of a substance
- It is typically expressed in grams per mole (g/mol)
- The molar mass of an element is numerically equal to its atomic mass in atomic mass units (amu or u)
- The molar mass of a compound is the sum of the molar masses of all the atoms in its chemical formula
Calculating Molar Mass
- To calculate the molar mass of a compound, add the atomic masses of each element in the formula, multiplied by its subscript
- Example: For water (H₂O), the molar mass is (2 × 1.008 g/mol for H) + (1 × 16.00 g/mol for O) = 18.016 g/mol
Mole Conversions
- Moles to mass: mass = moles × molar mass (m = n × M)
- Mass to moles: moles = mass / molar mass (n = m / M)
- Moles to particles: number of particles = moles × Avogadro's number (N = n × NA)
- Particles to moles: moles = number of particles / Avogadro's number (n = N / NA)
Stoichiometry
- Stoichiometry is the study of the quantitative relationships or ratios between two or more substances undergoing a physical or chemical change
- It is based on the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction
- Stoichiometry is essential for balancing chemical equations and determining the amount of reactants and products involved in a reaction
Balancing Chemical Equations
- A balanced chemical equation has the same number of atoms of each element on both sides of the equation
- Balancing is achieved by adding coefficients in front of the chemical formulas
- Never change the subscripts within a chemical formula when balancing an equation
- Follow a systematic approach: Balance metals, then non-metals, then hydrogen, and finally oxygen
Stoichiometric Coefficients
- The coefficients in a balanced chemical equation represent the relative number of moles of each reactant and product
- These coefficients are used to determine the mole ratios between substances in the reaction
Mole Ratios
- A mole ratio is a conversion factor derived from the coefficients of a balanced chemical equation
- It is used to convert between moles of one substance and moles of another substance in a chemical reaction
- Example: In the reaction 2H₂(g) + O₂(g) → 2H₂O(g), the mole ratio between H₂ and H₂O is 2:2, or 1:1
- To perform stoichiometric calculations, convert given quantities to moles, use mole ratios to find moles of desired substances, and then convert back to the desired units
Limiting Reactant
- The limiting reactant is the reactant that is completely consumed in a chemical reaction
- It determines the maximum amount of product that can be formed
- The other reactants are present in excess
- To identify the limiting reactant, calculate the moles of each reactant and compare their ratios to the stoichiometric ratios in the balanced equation
- The reactant that would produce the least amount of product is the limiting reactant
Theoretical Yield
- The theoretical yield is the maximum amount of product that can be produced from a given amount of limiting reactant
- It is calculated using stoichiometry based on the balanced chemical equation
Actual Yield
- The actual yield is the amount of product that is actually obtained from a chemical reaction
- It is often less than the theoretical yield due to factors such as incomplete reactions, side reactions, and loss of product during purification
Percent Yield
- The percent yield is the ratio of the actual yield to the theoretical yield, expressed as a percentage
- Percent yield = (Actual yield / Theoretical yield) × 100%
- It indicates the efficiency of a chemical reaction
Empirical Formula
- The empirical formula is the simplest whole-number ratio of atoms in a compound
- To determine the empirical formula:
- Convert the mass percentages of each element to grams
- Convert grams to moles using the molar mass of each element
- Divide each mole value by the smallest mole value to obtain the simplest mole ratio
- If necessary, multiply the ratios by a whole number to obtain whole-number subscripts
Molecular Formula
- The molecular formula is the actual number of atoms of each element in a molecule
- It is a whole-number multiple of the empirical formula
- To determine the molecular formula:
- Calculate the empirical formula
- Determine the molar mass of the empirical formula
- Divide the molar mass of the compound by the molar mass of the empirical formula to get a whole number (n)
- Multiply the subscripts in the empirical formula by n to obtain the molecular formula
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