The Mole Concept and Molar Mass

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Questions and Answers

In the balanced chemical equation $N_2 + 3H_2 \rightarrow 2NH_3$, if you have 6 moles of $H_2$, how many moles of $NH_3$ can be produced?

  • 2 moles
  • 6 moles
  • 4 moles (correct)
  • 3 moles

Consider the reaction $2CO(g) + O_2(g) \rightarrow 2CO_2(g)$. If 4 moles of $CO$ and 3 moles of $O_2$ are initially present, which reactant is the limiting reactant?

  • CO (correct)
  • Neither, both will be consumed at the same rate.
  • CO_2
  • O_2

A compound is found to contain 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is its empirical formula?

  • $C_3H_8O$
  • $CH_2O$ (correct)
  • $CHO_2$
  • $C_2H_4O_3$

If the actual yield of a reaction is 15 grams and the theoretical yield is 20 grams, what is the percent yield?

<p>75% (D)</p> Signup and view all the answers

How many grams of NaCl are present in 0.25 moles of NaCl? (Molar mass of NaCl = 58.44 g/mol)

<p>14.61 g (C)</p> Signup and view all the answers

What is the molar mass of $Ca(OH)_2$? (Molar mass of Ca = 40.08 g/mol, O = 16.00 g/mol, H = 1.008 g/mol)

<p>74.096 g/mol (C)</p> Signup and view all the answers

If the empirical formula of a compound is $CH_2$ and its molar mass is 56 g/mol, what is its molecular formula?

<p>$C_4H_8$ (C)</p> Signup and view all the answers

In the reaction $A + 2B \rightarrow C$, if 1 mole of A reacts with 2 moles of B to produce 1 mole of C, what is the mole ratio of B to C?

<p>2:1 (D)</p> Signup and view all the answers

How many molecules are there in 0.5 moles of $O_2$?

<p>3.011 x $10^{23}$ molecules (C)</p> Signup and view all the answers

What is the definition of the limiting reactant in a chemical reaction?

<p>The reactant that is completely consumed and determines the amount of product formed. (B)</p> Signup and view all the answers

Flashcards

What is a mole?

The amount of substance, defined as exactly 6.02214076 × 10²³ elementary entities (Avogadro's number).

What is molar mass?

The mass of one mole of a substance, typically expressed in grams per mole (g/mol).

What is a balanced chemical equation?

A balanced equation has the same number of atoms of each element on both sides.

What is a mole ratio?

A conversion factor derived from the coefficients of a balanced chemical equation, used to convert between moles of different substances.

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What is the limiting reactant?

The reactant that is completely consumed in a chemical reaction and determines the maximum amount of product that can be formed.

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What is theoretical yield?

The maximum amount of product that can be produced from a given amount of limiting reactant, calculated using stoichiometry.

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What is actual yield?

The amount of product actually obtained from a chemical reaction, often less than the theoretical yield.

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What is percent yield?

The ratio of the actual yield to the theoretical yield, expressed as a percentage, indicating reaction efficiency.

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What is an empirical formula?

The simplest whole-number ratio of atoms in a compound.

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What is the molecular formula?

The actual number of atoms of each element in a molecule; a whole-number multiple of the empirical formula.

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Study Notes

  • The mole concept is a way of expressing the amount of a substance
  • Stoichiometry deals with the quantitative relationships between reactants and products in chemical reactions

The Mole

  • A mole (symbol: mol) is the base unit of amount of substance in the International System of Units (SI)
  • It is defined as exactly 6.02214076 × 10²³ elementary entities
  • This number is known as Avogadro's constant (NA)
  • Elementary entities can be atoms, molecules, ions, or other specified particles
  • One mole of any substance contains the same number of entities as there are atoms in 12 grams of carbon-12

Molar Mass

  • Molar mass (M) is the mass of one mole of a substance
  • It is typically expressed in grams per mole (g/mol)
  • The molar mass of an element is numerically equal to its atomic mass in atomic mass units (amu or u)
  • The molar mass of a compound is the sum of the molar masses of all the atoms in its chemical formula

Calculating Molar Mass

  • To calculate the molar mass of a compound, add the atomic masses of each element in the formula, multiplied by its subscript
  • Example: For water (Hâ‚‚O), the molar mass is (2 × 1.008 g/mol for H) + (1 × 16.00 g/mol for O) = 18.016 g/mol

Mole Conversions

  • Moles to mass: mass = moles × molar mass (m = n × M)
  • Mass to moles: moles = mass / molar mass (n = m / M)
  • Moles to particles: number of particles = moles × Avogadro's number (N = n × NA)
  • Particles to moles: moles = number of particles / Avogadro's number (n = N / NA)

Stoichiometry

  • Stoichiometry is the study of the quantitative relationships or ratios between two or more substances undergoing a physical or chemical change
  • It is based on the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction
  • Stoichiometry is essential for balancing chemical equations and determining the amount of reactants and products involved in a reaction

Balancing Chemical Equations

  • A balanced chemical equation has the same number of atoms of each element on both sides of the equation
  • Balancing is achieved by adding coefficients in front of the chemical formulas
  • Never change the subscripts within a chemical formula when balancing an equation
  • Follow a systematic approach: Balance metals, then non-metals, then hydrogen, and finally oxygen

Stoichiometric Coefficients

  • The coefficients in a balanced chemical equation represent the relative number of moles of each reactant and product
  • These coefficients are used to determine the mole ratios between substances in the reaction

Mole Ratios

  • A mole ratio is a conversion factor derived from the coefficients of a balanced chemical equation
  • It is used to convert between moles of one substance and moles of another substance in a chemical reaction
  • Example: In the reaction 2Hâ‚‚(g) + Oâ‚‚(g) → 2Hâ‚‚O(g), the mole ratio between Hâ‚‚ and Hâ‚‚O is 2:2, or 1:1
  • To perform stoichiometric calculations, convert given quantities to moles, use mole ratios to find moles of desired substances, and then convert back to the desired units

Limiting Reactant

  • The limiting reactant is the reactant that is completely consumed in a chemical reaction
  • It determines the maximum amount of product that can be formed
  • The other reactants are present in excess
  • To identify the limiting reactant, calculate the moles of each reactant and compare their ratios to the stoichiometric ratios in the balanced equation
  • The reactant that would produce the least amount of product is the limiting reactant

Theoretical Yield

  • The theoretical yield is the maximum amount of product that can be produced from a given amount of limiting reactant
  • It is calculated using stoichiometry based on the balanced chemical equation

Actual Yield

  • The actual yield is the amount of product that is actually obtained from a chemical reaction
  • It is often less than the theoretical yield due to factors such as incomplete reactions, side reactions, and loss of product during purification

Percent Yield

  • The percent yield is the ratio of the actual yield to the theoretical yield, expressed as a percentage
  • Percent yield = (Actual yield / Theoretical yield) × 100%
  • It indicates the efficiency of a chemical reaction

Empirical Formula

  • The empirical formula is the simplest whole-number ratio of atoms in a compound
  • To determine the empirical formula:
    • Convert the mass percentages of each element to grams
    • Convert grams to moles using the molar mass of each element
    • Divide each mole value by the smallest mole value to obtain the simplest mole ratio
    • If necessary, multiply the ratios by a whole number to obtain whole-number subscripts

Molecular Formula

  • The molecular formula is the actual number of atoms of each element in a molecule
  • It is a whole-number multiple of the empirical formula
  • To determine the molecular formula:
    • Calculate the empirical formula
    • Determine the molar mass of the empirical formula
    • Divide the molar mass of the compound by the molar mass of the empirical formula to get a whole number (n)
    • Multiply the subscripts in the empirical formula by n to obtain the molecular formula

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