The Hall Effect
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Questions and Answers

Who discovered the Hall effect?

  • James Clerk Maxwell
  • Edwin Hall (correct)
  • Johns Hopkins University
  • Baltimore, Maryland

What is the Hall effect?

  • Production of a potential difference in the direction of an electric current
  • Production of a potential difference across an electrical conductor transverse to an electric current and an applied magnetic field (correct)
  • Production of a potential difference along the length of an electrical conductor
  • Production of a potential difference due to temperature difference in a conductor

What does the Hall coefficient represent?

  • Ratio of induced electric field to the product of current density and applied magnetic field (correct)
  • Ratio of induced magnetic field to the product of current density and applied electric field
  • Ratio of induced current to the product of magnetic field and applied electric field
  • Ratio of induced current to the product of electric field and applied magnetic field

What does the Hall coefficient depend on?

<p>Type, number, and properties of the charge carriers in the current (D)</p> Signup and view all the answers

When was the modern theory of electromagnetism systematized?

<p>1861-1862 (C)</p> Signup and view all the answers

How did Meißner and Ochsenfeld discover the Meissner effect?

<p>By measuring the magnetic field distribution outside superconducting tin and lead samples (B)</p> Signup and view all the answers

What is the Meissner effect?

<p>The expulsion of a magnetic field from a superconductor during its transition to the superconducting state (B)</p> Signup and view all the answers

What happens to the interior magnetic fields of superconducting samples during the Meissner effect?

<p>They are cancelled nearly all (B)</p> Signup and view all the answers

What does the Meissner effect demonstrate about superconductors?

<p>They are more than just perfect conductors (C)</p> Signup and view all the answers

When does the Meissner state break down?

<p>When the applied magnetic field is too strong (A)</p> Signup and view all the answers

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