The Grace of Mathematics

$F = ma$

$\frac{{d^2x}},{{dt^2}} + \omega^2x = 0$ (correct)

$E = mc^2$

$f(x) = -4(x + 3)­­­­^2 + 2$

$f(x) = -4(x + 3)­­­­^2 + 2$

$F = ma$

$E = mc^2$ (correct)

$\frac{{d^2x}},{{dt^2}} + \omega^2x = 0$

$E = mc^2$

$F = ma$ (correct)

$f(x) = -4(x + 3)­­­­^2 + 2$

$\frac{{d^2x}},{{dt^2}} + \omega^2x = 0$

<p>$f(x) = -4(x + 3)­­­­^2 + 2$</p> Signup and view all the answers

<p>$\frac{{d^2x}},{{dt^2}} + \omega^2x = 0$</p> Signup and view all the answers