Test 3 Review: Factoring and Solving
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Questions and Answers

Which of the following is the correct complete factorization of $x^2(x+2) - 16(x+2)$?

  • $(x^2 + 16)(x+2)$
  • $(x+4)(x-4)(x+2)$ (correct)
  • $(x^2-16)(x+2)$
  • $(x+4)(x-4)$

What are the zeroes of the polynomial $(x+4)(x-4)(5x+6)(5x-6) = 0$?

  • $x = -4, 4, -5/6, 5/6$
  • $x = -4, 4, -5, 5$
  • $x = -4, 4, -6/5, 6/5$ (correct)
  • $x = -4, -4, -6, 6$

Given the vertex form of a quadratic equation $y = a(x - 3)^2 + 5$, and the point (0, -4) on the parabola, what is the value of 'a'?

  • -2
  • 2
  • 1
  • -1 (correct)

For the quadratic equation derived from vertex form $0 = -(x - 3)^2 + 5$, what are the real solutions for x?

<p>$x = 3 \pm \sqrt{5}$ (C)</p> Signup and view all the answers

Given the polynomial $f(x) = x^4 - 2x^3 + 28x^2 - 72x - 288$, and knowing x = 4 and x = -2 are real roots, what are the remaining complex roots?

<p>$x = \pm 6i$ (A)</p> Signup and view all the answers

Given 3x^2 - 15x + 2x - 10, which of the following represents the correctly factored form?

<p>$(3x + 2)(x - 5)$ (C)</p> Signup and view all the answers

If a polynomial has factors of $(x+4)$, $(x-4)$, $(5x+6)$ and $(5x-6)$, what is the nature of its roots?

<p>There are two integer and two rational roots. (C)</p> Signup and view all the answers

Given the equation $y = a(x-3)^2 + 5$, how does changing the value of 'a' affect the parabola's graph?

<p>Affects the vertical stretch/compression and whether the parabola opens upward or downward. (C)</p> Signup and view all the answers

If synthetic division is used on the polynomial $f(x) = x^4 - 2x^3 + 28x^2 - 72x - 288$ with root x = 4, what is the resulting polynomial?

<p>$x^3 + 2x^2 + 36x + 72$ (B)</p> Signup and view all the answers

The complex roots of a polynomial are found to be $x = \pm 6i$. What does this imply about the graph of the polynomial function in the real coordinate plane?

<p>The graph does not intersect the x-axis at x = 6 or x = -6. (B)</p> Signup and view all the answers

Flashcards

Factor by Grouping

Grouping terms with common factors to simplify expressions.

Synthetic Division

Replacing a polynomial with a simpler equivalent expression.

Zeros of a Function

Solutions to a polynomial equation where the function equals zero.

Complex Numbers

Numbers in the form a + bi, where 'a' and 'b' are real numbers and 'i' is the imaginary unit.

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Study Notes

  • Test 3, Version 2 is set for February 2025.
  • The test has a total score of 43 points.

Factoring Completely

  • Example a: x²(x+2) - 16(x+2) factors to (x²-16)(x+2), which further factors to (x+4)(x-4)(x+2).
  • Example b: 3x² - 15x + 2x - 10 factors to 3x(x-5) + 2(x-5), which results in (3x+2)(x-5).

Division and Factoring

  • (x+4)(x-4)(5x+6)(5x-6) = 0 gives the solutions x = 4, x = -4, x = -6/5, and x = 6/5.

Solving for y

  • Given y = a(x-3)² + 5, using the point (0, -4) to solve for a yields a = -1.
  • Therefore, y = -(x-3)² + 5. Setting y to 0 gives 0 = -(x-3)² + 5.
  • Manipulating the equation -5 = -(x-3)² leads to 5 = (x-3)².
  • Taking the square root gives ±√5 = x - 3, so x = 3 ± √5.

Finding Complex Zeros

  • The function f(x) = x⁴ - 2x³ + 28x² - 72x - 288 has complex zeros.
  • Using a calculator and graph, two real roots are found: x = -2 and x = 4.
  • Applying synthetic division with x = 4 and x = -2 helps factor the polynomial.
  • The synthetic division results in the quadratic x² + 36 = 0.
  • Solving x² + 36 = 0 yields x² = -36, so x = ±6i.

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Description

Review for Test 3 covering factoring techniques and solving algebraic equations. Includes factoring completely, division and factoring, solving for y, and finding complex zeros. Examples provided for each method.

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