tanh(x) and hyperbolic functions

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Questions and Answers

Given $x \in (-1, 1)$, which of the following expressions is equivalent to $\tanh^{-1}(x)$?

  • $\frac{1}{2} \log(\frac{1+x}{1-x})$ (correct)
  • $\frac{1}{2} \log(\frac{1-x}{1+x})$
  • $\log(x - \sqrt{x^2 + 1})$
  • $\log(x + \sqrt{x^2 + 1})$

Which hyperbolic function is defined as $\frac{1}{2}(e^x - e^{-x})$?

  • $\sinh(x)$ (correct)
  • $\text{sech}(x)$
  • $\tanh(x)$
  • $\cosh(x)$

Which of the following is the correct definition of $\tanh(x)$?

  • $\frac{\cosh(x)}{\sinh(x)}$
  • $\frac{1}{\sinh(x) \cdot \cosh(x)}$
  • $\frac{\sinh(x)}{\cosh(x)}$ (correct)
  • $\sinh(x) \cdot \cosh(x)$

Given that $\tanh(x) = \frac{e^x - e^{-x}}{e^x + e^{-x}}$, which expression is equivalent to $\tanh(x)$?

<p>$\frac{e^{2x} - 1}{e^{2x} + 1}$ (C)</p> Signup and view all the answers

Which function represents $\cosh(x)$?

<p>$\frac{e^x + e^{-x}}{2}$ (B)</p> Signup and view all the answers

If $\tanh(x) = y$, express $x$ in terms of $y$.

<p>$x = \frac{1}{2} \ln(\frac{1+y}{1-y})$ (B)</p> Signup and view all the answers

Given the definitions of $\sinh(x)$ and $\cosh(x)$, which of the following identities is correct?

<p>$\cosh^2(x) - \sinh^2(x) = 1$ (D)</p> Signup and view all the answers

How is $\tanh(x)$ related to $\sinh(x)$ and $\cosh(x)$?

<p>$\tanh(x) = \frac{\sinh(x)}{\cosh(x)}$ (A)</p> Signup and view all the answers

If $f(x) = \tanh(x)$, what is the range of $f(x)$?

<p>$(-1, 1)$ (A)</p> Signup and view all the answers

Simplify the expression: $\frac{\cosh(2x) + 1}{\sinh(2x)}$

<p>$\coth(x)$ (B)</p> Signup and view all the answers

Flashcards

tanh(x)

It is defined as sinh(x) / cosh(x), analogous to tan(x) = sin(x) / cos(x).

sinh(x)

This is one half times (e to the x, minus e to the minus x).

cosh(x)

It is expressed as one half times (e to the x, plus e to the minus x).

tanh⁻¹(x)

The inverse hyperbolic tangent function.

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tanh⁻¹(x) formula

For x ∈ (-1, 1), tanh⁻¹(x) = (1/2)log((1+x)/(1-x)).

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Study Notes

  • Correct answer is option 3: 1/2 log((1+x)/(1-x))
  • 30% of people got it right

Concepts

  • tanh(x) = sinh(x) / cosh(x)
  • sinh(x) = 1/2 * (e^x - e^-x)
  • cosh(x) = 1/2 * (e^x + e^-x)

Solution

  • tanh(x) is also equal to (e^x - e^-x) / (e^x + e^-x) or (e^2x - 1) / (e^2x + 1)

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