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Surface Areas & Volumes Chapter 12 Quiz
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Surface Areas & Volumes Chapter 12 Quiz

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Questions and Answers

What is the ratio of the volume of the smaller cone to the whole cone when a solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base?

  • 1:6
  • 1:4
  • 1:8 (correct)
  • 1:2
  • If two cubes, each with a side length of 4 cm, are joined end to end, what is the surface area of the resulting cuboid?

  • 56 cm²
  • 40 cm²
  • 48 cm² (correct)
  • 64 cm²
  • What is the height of the resulting cuboid when a solid right circular cone is cut into two parts at the middle of its height?

  • 2 cm
  • 4 cm (correct)
  • 5 cm
  • 3 cm
  • If the length of the resulting cuboid is 8 cm and the breadth is 4 cm, what is its total surface area?

    <p>160 cm²</p> Signup and view all the answers

    What is the ratio of the radius of the small cone to its height when a solid right circular cone is cut into two parts at the middle?

    <p>1:2</p> Signup and view all the answers

    Study Notes

    Solid Right Circular Cone Cutting

    • When a solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base, the ratio of the volume of the smaller cone to the whole cone is 1:7.
    • The height of the resulting cone is half of the original height.

    Cuboid Formation

    • When two cubes, each with a side length of 4 cm, are joined end to end, a cuboid is formed.
    • The length of the resulting cuboid is 8 cm and the breadth is 4 cm.
    • The total surface area of the cuboid is 96 cm².

    Ratio of Radius to Height

    • When a solid right circular cone is cut into two parts at the middle of its height, the ratio of the radius of the small cone to its height is 1:1.

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    Description

    Test your knowledge on problems related to finding the total surface area (TSA) or curved surface area (CSA) volume of combinations of solid shapes. Determine the ratio of volumes when a solid right circular cone is cut into two parts at the middle of its height. Practice solving similar problems and strengthen your understanding.

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