Stoichiometry Practice Stations

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Questions and Answers

Given the unbalanced equation $N_2 + H_2 \rightarrow NH_3$, what is the mole ratio of $H_2$ to $NH_3$ in the balanced reaction?

3:2

If 25.0 grams of ammonium nitrate ($NH_4NO_3$) decomposes, according to the unbalanced equation $NH_4NO_3 \rightarrow N_2O + H_2O$, what mass of water ($H_2O$) is produced?

11.3 g $H_2O$

For the reaction $TiO_2 + C + Cl_2 \rightarrow TiCl_4 + CO_2$, how many grams of chlorine gas ($Cl_2$) are needed to react completely with 2.35 moles of titanium dioxide ($TiO_2$)?

333 g $Cl_2$

In the reaction $NH_3 + O_2 \rightarrow H_2O + NO$, if 15.8 grams of ammonia ($NH_3$) reacts with excess oxygen, how many moles of water vapor ($H_2O$) are expected to form?

<p>1.39 mol $H_2O$</p> Signup and view all the answers

For the combustion of propane ($C_3H_8$) according to the unbalanced equation $C_3H_8 + O_2 \rightarrow H_2O + CO_2$, how many moles of oxygen ($O_2$) are required to completely combust 1.27 moles of propane?

<p>6.35 mol $O_2$</p> Signup and view all the answers

If you have 4.66 g of $N_2$, determine how many grams of $H_2$ are needed to fully react and produce $NH_3$?

<p>1.00 g $H_2$</p> Signup and view all the answers

For the reaction $2NaOH + H_2SO_4 \rightarrow 2H_2O + Na_2SO_4$, how does increasing the amount of $H_2SO_4$ affect the amount of $Na_2SO_4$ produced, assuming $NaOH$ is the limiting reactant?

<p>It does not affect the amount of $Na_2SO_4$ produced.</p> Signup and view all the answers

In the reaction $N_2 + 3H_2 \rightarrow 2NH_3$, if you start with 2 moles of $N_2$ and 5 moles of $H_2$, identify the limiting reactant.

<p>$H_2$</p> Signup and view all the answers

Consider the reaction $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$. If 10 moles of $C_3H_8$ are reacted with 40 moles of $O_2$, what is the theoretical yield of $CO_2$ in moles?

<p>24 moles</p> Signup and view all the answers

If the actual yield of $H_2O$ in the reaction $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$ is 14.4 moles when 5 moles of $C_3H_8$ are reacted, what is the percent yield of the reaction?

<p>72%</p> Signup and view all the answers

For the reaction $2K + Cl_2 \rightarrow 2KCl$, if 7.84 grams of $K$ are allowed to react with excess $Cl_2$, what is the theoretical yield of $KCl$ in grams?

<p>15.04 g $KCl$</p> Signup and view all the answers

If the percent yield of a reaction is 85% and the theoretical yield is 40.0 grams, what is the actual yield of the product?

<p>34.0 grams</p> Signup and view all the answers

Given the balanced equation $4NH_3 + 5O_2 \rightarrow 4NO + 6H_2O$, if 34.0 grams of ammonia ($NH_3$) are reacted with excess oxygen, what mass of water ($H_2O$) is produced?

<p>54.0g $H_2O$</p> Signup and view all the answers

For the reaction $2H_2 + O_2 \rightarrow 2H_2O$, if you start with 4.0 grams of $H_2$ and 32.0 grams of $O_2$, which reactant will be completely consumed?

<p>$H_2$</p> Signup and view all the answers

Consider the reaction $C_6H_{12}O_6 \rightarrow 2C_2H_5OH + 2CO_2$. If 90.0 g of $C_6H_{12}O_6$ goes to completion, what is the theoretical mass yield of $C_2H_5OH$?

<p>46.0 g</p> Signup and view all the answers

In a chemical reaction, what does the term 'stoichiometric coefficients' refer to, and how are they used in stoichiometric calculations?

<p>The numbers in front of the chemical formulas in a balanced equation; used to determine mole ratios.</p> Signup and view all the answers

How does the concept of 'limiting reactant' influence the maximum amount of product that can be formed in a chemical reaction?

<p>It determines the maximum amount of product.</p> Signup and view all the answers

Explain the difference between 'theoretical yield' and 'actual yield' in a chemical reaction, and what does the percent yield represent?

<p>Theoretical yield is maximum product, actual yield is what's obtained; percent yield is the ratio as a percentage.</p> Signup and view all the answers

If a reaction has a high percent yield, does this always indicate that the reaction was performed without any errors or loss of product? Explain.

<p>No, only that there were minimal losses.</p> Signup and view all the answers

A student performs a reaction and calculates a theoretical yield of 25.0 grams of product. If their actual yield is 20.0 grams, explain two potential reasons why the actual yield is less than the theoretical yield.

<p>Incomplete reaction, product loss.</p> Signup and view all the answers

Consider a scenario where two different reactions produce the same product. Explain how stoichiometry can be used to determine which reaction is more efficient in producing the desired product.

<p>Compare mole ratios.</p> Signup and view all the answers

Explain why it is important to balance a chemical equation before performing stoichiometric calculations.

<p>To ensure the law of conservation of mass.</p> Signup and view all the answers

In the context of stoichiometry, what is the significance of Avogadro's number, and how is it used in converting between moles and number of particles (atoms, molecules, ions)?

<p>Significant for molar conversions, used to convert moles to a number of particles.</p> Signup and view all the answers

Describe how the concepts of stoichiometry are applied in real-world scenarios, outside of a chemistry laboratory setting.

<p>Dosage calculations, industrial processes.</p> Signup and view all the answers

How does the presence of impurities in a reactant affect the accuracy of stoichiometric calculations used to predict the amount of product formed?

<p>Impure reactants reduce accuracy.</p> Signup and view all the answers

Flashcards

Stoichiometry

The quantitative relationship between two or more substances during a chemical reaction.

Steps for Stoichiometry Problems

  1. Balance the equation.
  2. Convert grams to moles.
  3. Use the molar ratio to convert moles of the given substance to moles of the desired substance.
  4. Convert moles back to grams if necessary.

Mole (mol)

A measure of the amount of substance, 1 mole contains Avogadro's number (6.022 x 10^23) of particles.

Molar Mass

The mass of one mole of a substance, usually expressed in grams per mole (g/mol).

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Molar Ratio

The ratio of moles between two substances in a balanced chemical equation.

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Balanced Equation

A chemical equation where the number of atoms for each element is the same on both sides of the equation.

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Unbalanced Equation for Sodium Hydroxide and Sulfuric Acid

NaOH + H2SO4 → H2O + Na2SO4

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Balanced Equation for Sodium Hydroxide and Sulfuric Acid

2 NaOH + H2SO4 → 2 H2O + Na2SO4

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Unbalanced Equation for Nitrogen and Hydrogen

N2 + H2 → NH3

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Balanced Equation for Nitrogen and Hydrogen

N2 + 3 H2 → 2 NH3

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Unbalanced Equation for Ammonium Nitrate

NH4NO3 → N2O + H2O

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Balanced Equation for Ammonium Nitrate

NH4NO3 → N2O + 2 H2O

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Unbalanced Equation for Titanium Dioxide

TiO2 + C + Cl2 → TiCl4 + CO2

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Balanced Equation for Titanium Dioxide

TiO2 + C + 2 Cl2 → TiCl4 + CO2

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Unbalanced Equation for Ammonia and Oxygen

NH3 + O2 → H2O + NO

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Balanced Equation for Ammonia and Oxygen

4 NH3 + 5 O2 → 6 H2O + 4 NO

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Unbalanced Equation for Propane

C3H8 + O2 → H2O + CO2

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Balanced Equation for Propane

C3H8 + 5 O2 → 4 H2O + 3 CO2

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Study Notes

  • Stoichiometry practice stations are designed for collaborative learning at individual paces
  • These stations help students practice and become proficient in stoichiometric calculations
  • Answer keys and problem setups are printed on the back of each station

Topics Covered

  • Mole-to-mole calculations
  • Gram-to-mole calculations
  • Mole-to-gram calculations
  • Gram-to-gram calculations
  • Problems involving balancing chemical equations

Tips for Learning Stations

  • At least four copies of each station should be printed and placed around the room
  • Six copies are recommended for more challenging stations
  • Answer keys are provided on the back of each station
  • Students can start at any station
  • Stations do not need to be completed sequentially
  • Students should bring their own notebook paper, calculator, and periodic table
  • Students work through problems together and number the stations they are working on
  • Students should check their solutions before moving to the next station
  • Students can work backwards from the key for the problem if they encounter and error
  • Assistance from the instructor should be sought if the error cannot be identified

Station #1

  • Determine how many moles of sodium sulfate are formed from 223 g of sodium hydroxide
  • Reaction: 2 NaOH + H2SO4 → 2 H2O + Na2SO4
  • Solution: 223 g NaOH * (1 mol NaOH / 40.00 g NaOH) * (1 mol Na2SO4 / 2 mol NaOH) = 2.79 mol Na2SO4
  • The molar mass of NaOH is approximately 40.00 g/mol

Station #2

  • Determine how many grams of hydrogen are needed to react completely with 1.40 g of nitrogen to produce ammonia
  • Reaction: N2 + 3 H2 → 2 NH3
  • Solution: 1.40 g N2 * (1 mol N2 / 28.02 g N2) * (3 mol H2 / 1 mol N2) * (2.02 g H2 / 1 mol H2) = 0.303 g H2
  • The molar mass of N2 is approximately 28.02 g/mol, H2 is approximately 2.02 g/mol

Station #3

  • Determine the mass in grams of water produced from the decomposition of 25.0 g of ammonium nitrate
  • Reaction: NH4NO3 → N2O + 2 H2O
  • Solution: 25.0 g NH4NO3 * (1 mol NH4NO3 / 80.06 g NH4NO3) * (2 mol H2O / 1 mol NH4NO3) * (18.02 g H2O / 1 mol H2O) = 11.3 g H2O
  • The molar mass of NH4NO3 is approximately 80.06 g/mol, H2O is approximately 18.02 g/mol

Station #4

  • Determine the mass in grams of chlorine gas needed to react with 2.35 moles of titanium dioxide
  • Reaction: TiO2 + C + 2 Cl2 → TiCl4 + CO2
  • Solution: 2.35 mol TiO2 * (2 mol Cl2 / 1 mol TiO2) * (70.90 g Cl2 / 1 mol Cl2) = 333 g Cl2
  • The molar mass of Cl2 is approximately 70.90 g/mol

Station #5

  • Determine how many moles of water vapor are formed from the reaction between 15.8 g of ammonia and excess oxygen
  • Reaction: 4 NH3 + 5 O2 → 6 H2O + 4 NO
  • Solution: 15.8 g NH3 * (1 mol NH3 / 17.04 g NH3) * (6 mol H2O / 4 mol NH3) = 1.39 mol H2O
  • The molar mass of NH3 is approximately 17.04 g/mol

Station #6

  • Determine how many moles of oxygen are required to completely combust 1.27 moles of propane ($C_3H_8$)
  • Reaction: $C_3H_8$ + 5 $O_2$ → 4 $H_2O$ + 3 $CO_2$
  • Solution: 1.27 mol $C_3H_8$ * (5 mol $O_2$ / 1 mol $C_3H_8$) = 6.35 mol $O_2$

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