6 Questions
What is the voltage across the resistor at t = 0+ if a unit step voltage is applied to a series RL circuit with zero initial conditions?
It is zero
What happens to the current through the resistor in the steady state when a unit step voltage is applied to a series RL circuit with zero initial conditions?
It reaches a constant value
Is it possible for the current to be oscillatory in a series RL circuit with zero initial conditions when a unit step voltage is applied?
No, it is never oscillatory
What is the energy stored in the inductor in the steady state when a unit step voltage is applied to a series RL circuit with zero initial conditions?
Zero
What is the behavior of the inductor at the instance t = 0+ in a series RL circuit when a unit step voltage is applied with zero initial conditions?
Acts as a short circuit
What happens to the resistor current eventually in a series RL circuit when a unit step voltage is applied with zero initial conditions?
It reaches a steady value
Study Notes
Unit Step Voltage in a Series RL Circuit
- A unit step voltage is applied to a series RL circuit with zero initial conditions at t = 0.
- The inductor current is zero at t = 0- and t = 0+ (L(0^-)=0=L(0^+)).
Voltage and Current in the Resistor
- At t = 0+, the voltage across the resistor is zero (correct answer).
- The resistor current does not necessarily fall to zero eventually (opposite of option D).
Oscillatory Current and Energy Storage
- The current in the circuit may or may not be oscillatory (option A is possible but not certain).
- In the steady state, the energy stored in the inductor is not necessarily zero (opposite of option C).
Analysis of a series RL circuit with zero initial conditions when a unit step voltage is applied at t = 0. Determine the behavior of the current and voltage across the resistor and inductor.
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