Semiconductor Physics MCQs
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Questions and Answers

A P-type semiconductor has acceptor levels 57 meV above the valence band. What is the maximum wavelength of light required to create a hole?

  • 57 Å
  • 217100 Å (correct)
  • 11.61×10-33 Å
  • 57×10-3 Å
  • What is the current in the circuit?

  • 5/10 A
  • 5/20 A (correct)
  • 5/50 A
  • 5/40 A
  • What should be the value of the resistor R, connected in series with the diode for obtaining maximum current?

  • 5 Ω (correct)
  • 1.5 Ω
  • 6.67 Ω
  • 200 Ω
  • For a transistor amplifier in common emitter configuration with a load impedance of 1 kΩ, what is the current gain if hfe = 50 and hoe = 25 μΑ/V?

    <p>-48.78</p> Signup and view all the answers

    What will be the output voltage of the amplifier using an NPN transistor with current gain β = 100 in common emitter configuration?

    <p>10 V</p> Signup and view all the answers

    What type of semiconductor is indicated if the concentrations of electrons and holes are 8 × 10^18/m3 and 5 × 10^18/m, respectively, with mobilities of electrons and holes at 2.3 m2/volt-sec and 0.01 m2/volt-sec?

    <p>N-type and its resistivity is 0.034 ohm-metre</p> Signup and view all the answers

    Study Notes

    Semiconductor Physics

    • A P-type semiconductor with acceptor levels 57 meV above the valence band requires a minimum energy of light to create a hole, corresponding to a maximum wavelength of 217100 Å.

    Current and Diodes

    • The current in a circuit can be calculated by considering the voltage drop across a diode, which can have a constant voltage drop of 0.5 V at all currents.
    • A diode with a maximum power rating of 100 milliwatts requires a series resistor with a value of 6.67 Ω to obtain maximum current.

    Transistor Amplifiers

    • A transistor amplifier in common emitter configuration has a current gain (β) that depends on the load impedance, hfe, and hoe.
    • For a load impedance of 1 kΩ, hfe = 50, and hoe = 25 μΑ/V, the current gain is -48.78.
    • The output voltage of a common emitter configuration amplifier using an NPN transistor with β = 100 is dependent on the circuit configuration.

    Semiconductor Properties

    • The concentration of electrons and holes in a semiconductor affects its properties, with a concentration of 8 × 1018/m3 electrons and 5 × 1018/m3 holes resulting in a specific semiconductor type and resistivity.
    • The mobilities of electrons and holes, 2.3 m2/volt-sec and 0.01 m2/volt-sec respectively, also influence the semiconductor's properties.

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    Description

    Multiple choice questions on semiconductor physics, including p-type semiconductors, light required to create a hole, and diode circuits.

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