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What is the reciprocal identity of $ an heta$?
What is the reciprocal identity of $ an heta$?
- $rac{1}{rac{1}{ an heta}}$
- $rac{1}{ an^2 heta}$
- $rac{1}{ an heta}$ (correct)
- $rac{1}{ an^{-1} heta}$
For $ heta$, given that $rac{1}{ ext{Reciprocal of} an heta} = $
For $ heta$, given that $rac{1}{ ext{Reciprocal of} an heta} = $
- $rack heta^2}{1}$
- $rac{1}{ heta}$
- $ an heta$ (correct)
- $ heta$
What is the $ ext{Reciprocal of} ext(csc} heta?
What is the $ ext{Reciprocal of} ext(csc} heta?
- $ heta_{ heta}$
- $tan^{-1} heta$
- $rac{1}{ ext{Reciprocal of} heta}$ (correct)
- $ g heta$
What is the reciprocal identity of $ heta$
What is the reciprocal identity of $ heta$
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Study Notes
Reciprocal Identities
- sinθ\sin \thetasinθ is the reciprocal of cscθ\csc \thetacscθ, meaning sinθ=1cscθ\sin \theta = \frac{1}{\csc \theta}sinθ=cscθ1
- cscθ\csc \thetacscθ is the reciprocal of sinθ\sin \thetasinθ, meaning cscθ=1sinθ\csc \theta = \frac{1}{\sin \theta}cscθ=sinθ1
- cosθ\cos \thetacosθ is the reciprocal of secθ\sec \thetasecθ, meaning cosθ=1secθ\cos \theta = \frac{1}{\sec \theta}cosθ=secθ1
- secθ\sec \thetasecθ is the reciprocal of cosθ\cos \thetacosθ, meaning secθ=1cosθ\sec \theta = \frac{1}{\cos \theta}secθ=cosθ1
- tanθ\tan \thetatanθ is the reciprocal of cotθ\cot \thetacotθ, meaning tanθ=1cotθ\tan \theta = \frac{1}{\cot \theta}tanθ=cotθ1
- cotθ\cot \thetacotθ is the reciprocal of tanθ\tan \thetatanθ, meaning cotθ=1tanθ\cot \theta = \frac{1}{\tan \theta}cotθ=tanθ1
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