Radiology Inverse Square Law Flashcards
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Radiology Inverse Square Law Flashcards

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Questions and Answers

What is the inverse square law?

The intensity of the x-ray beam varies inversely with the square of the source to film distance.

What will be influenced if the source-to-film distance (SFD) is changed?

The density of the radiographs.

What are the two rules of thumb to maintain the original density when a change in SFD occurs?

  1. If SFD is doubled, the exposure time should be multiplied by 4. 2. If SFD is halved, exposure is divided by 4.

If an 8 inch PID with 15 mA, 80 kVp, and 0.01 impulses is changed to a 16 inch PID with the same mA and kVp, what would the impulses be?

<p>Double the impulses; 0.01 x 4 = 0.04 impulses.</p> Signup and view all the answers

If a 16 inch PID with 15 mA, 90 kVp, and 20 impulses is changed to an 8 inch PID, what would the impulses be?

<p>5 impulses; 20 / 4 = 5.</p> Signup and view all the answers

What does mA control?

<p>The quantity of number of x-rays produced.</p> Signup and view all the answers

What is the rule of thumb for changes in mA to maintain density?

<ol> <li>An increase of 5 mA will increase the number of x-rays produced, divide the time by 2. 2. A decrease in 5 mA will decrease the number of x-rays, multiply the time by 2.</li> </ol> Signup and view all the answers

If 5 mA at 0.30 seconds is increased to 10 mA, what is the new time?

<p>0.15 seconds; 0.30 / 2 = 0.15.</p> Signup and view all the answers

If 10 mA at 0.20 seconds is decreased to 5 mA, what is the new time?

<p>0.40 seconds; 0.20 x 2 = 0.40.</p> Signup and view all the answers

What does kVp control?

<p>Quality or penetrating power of x-rays; it is a minor factor in controlling quantity of x-rays.</p> Signup and view all the answers

A change in kVp will alter what?

<p>Density or quantity of x-rays produced.</p> Signup and view all the answers

What are the rules of thumb for kVp?

<ol> <li>If kVp is increased by 15 kVp, it will increase the number of x-rays; to maintain density, divide time by 2. 2. If kVp is decreased by 15, it will decrease the number of x-rays; multiply time by 2.</li> </ol> Signup and view all the answers

If 60 kVp at 0.50 seconds is increased to 75 kVp, what is the new time?

<p>0.25 seconds; 0.50 / 2 = 0.25.</p> Signup and view all the answers

If 85 kVp at 0.50 seconds is decreased to 70 kVp, what is the new time?

<p>0.30 seconds; 0.15 x 2 = 0.30.</p> Signup and view all the answers

A good radiograph was made using a source-to-film distance of 16 inches and an exposure of 20 seconds. If the source-to-film distance is decreased to 8 inches, what would the correct exposure time be?

<p>5 seconds; 20 / 4 = 5 seconds.</p> Signup and view all the answers

A radiograph is exposed using 85 kVp at 0.15 seconds. The kVp is decreased to 70 kVp. What will the new time be?

<p>0.30 seconds; 0.15 x 2 = 0.30 seconds.</p> Signup and view all the answers

If a satisfactory radiograph is produced using a source-to-film distance of 8 inches and an exposure time of 1 second, what would the correct exposure time for a source-to-film distance of 16 inches be?

<p>4 seconds; 1 x 4 = 4 seconds.</p> Signup and view all the answers

A diagnostic film produced using 90 kVp and 0.25 seconds. What exposure time is needed to produce the same film at 75 kVp?

<p>0.50 seconds; 0.25 x 2 = 0.50.</p> Signup and view all the answers

If a diagnostic radiograph is produced using 5 mA at 0.30 seconds, what exposure time is needed to produce the same film using 15 mA?

<p>0.075 seconds; for each increase of 5 mA, the time must be divided by 2, so 0.30 / 4 = 0.075.</p> Signup and view all the answers

Study Notes

Inverse Square Law

  • The intensity of the x-ray beam decreases as the distance from the source increases, specifically varying inversely with the square of the source-to-film distance (SFD).

Effects of Changing SFD

  • A change in SFD will directly influence the density of the radiographs produced.

Rules of Thumb for Changing SFD

  • Doubling the SFD requires an increase in exposure time by a factor of four.
  • Halving the SFD allows for a decrease in exposure time to one-fourth of the original duration.

Impulses Adjustment with SFD Change

  • When changing from an 8 inch PID to a 16 inch PID while maintaining the same mA and kVp, the impulses needed will double (e.g., 0.01 becomes 0.04).
  • Conversely, changing from a 16 inch PID to an 8 inch PID will require the impulses to be reduced to a quarter (e.g., 20 impulses becomes 5).

Milliamperes (mA) Control

  • mA controls the quantity or number of x-rays produced during exposure.

mA Adjustment Rules

  • An increase of 5 mA necessitates halving the exposure time to maintain density.
  • A decrease of 5 mA requires doubling the exposure time to preserve image quality.

Time Adjustment with mA Changes

  • If mA is increased from 5 to 10, the time is halved from 0.30 seconds to 0.15 seconds.
  • If mA decreases from 10 to 5, the time doubles from 0.20 seconds to 0.40 seconds.

Kilovoltage Peak (kVp) Control

  • kVp influences the quality and penetrating power of x-rays, playing a minor role in the quantity produced.

Density Adjustment with kVp Changes

  • A modification in kVp alters both the density and the quantity of x-rays generated.

kVp Adjustment Rules

  • Increasing kVp by 15 requires halving the exposure time to maintain density.
  • Decreasing kVp by 15 necessitates doubling the exposure time to achieve the same effect.

Time Adjustment with kVp Changes

  • If kVp increases from 60 to 75, exposure time is shortened from 0.50 seconds to 0.25 seconds.
  • Reducing kVp from 85 to 70 requires time to be adjusted from 0.15 seconds to 0.30 seconds.

SFD and Exposure Time Relationship

  • A satisfactory radiograph exposed at 16 inches for 20 seconds will only need 5 seconds when the SFD is reduced to 8 inches.
  • For an SFD of 16 inches, if starting from an exposure of 1 second at 8 inches, the time required becomes 4 seconds.

Final Time Adjustment Scenarios

  • Reducing kVp from 85 to 70 while maintaining exposure time requires multiplying the initial time (0.15 seconds) by 2, resulting in 0.30 seconds for the new exposure duration.
  • Producing a diagnostic radiograph with increased mA to 15 from 5 mA at 0.30 seconds requires dividing the time by 4, yielding 0.075 seconds for proper density maintenance.

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Study the fundamentals of the inverse square law in radiology with these flashcards. Explore key concepts such as the relationship between x-ray intensity and source-to-film distance, as well as practical rules of thumb for maintaining radiographic density. Perfect for radiology students and professionals looking to reinforce their knowledge.

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